Answer:
0.559 L
Explanation:
Step 1: Given data
- Moles of sodium iodide (n): 0.405 mol
- Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)
Step 2: Calculate the volume of solution (V)
The molarity is equal to the moles of solute divided by the liters of solution.
M = n/V
V = n/M
V = 0.405 mol/(0.724 mol/L) = 0.559 L
Answer:
The vocabulary terms are in the correct order.
Explanation:
The substances that undergo chang are called <em>reactants</em>. They are what create the products. Reactants are on the left side of the equation while the products are on the right side of the equation. The new substances are called <em>products</em>. In other words, what is produced? The products are produced. The reactant that will be used up first is called a <em>limiting reactant</em>. Why? Because it is what limits the reaction. It determines how much products can be made. The reactant that is left over then, is called the <em>excess reactant.</em> That is what is left in excess and does <u>not</u> determine how much product is made.
Calcium reacts gently with water to give hydrogen and calcium hydroxide, which is only slightly soluble, thus slows down the reaction.
It will be assumed that hydrochloric acid used is a dilute aqueous solution.
However, calcium reacts with hydrochloric acid to give calcium chloride which is readily soluble in water, and hydrogen, being a typical reaction of relatively active metals with acids.
Ca(s) + 2HCl(aq) -> CaCl2(aq) +H2(g) ↑ + heat
The clues that it is a chemical reaction could be:
- formation of a new substance, gaseous hydrogen
- disappearance of a metallic solid in the solution
- heat formed during the vigorous reaction.
As silver is below hydrogen in the electrochemical series, it will not be expected to react with dilute hydrocloric acid. (however, it dissolves in oxidizing acid such as nitric acid, but not displacing hydrogen as a product).
Answer:
ΔT = 1,41°C
Explanation:
For the reaction:
2HCl(aq) + Ba(OH)₂(aq) → BaCl₂(aq) + 2 H₂O(l); ΔH = –118 kJ.
If moles of reaction are:
HCl:
0,0500L×0,20M = 0,01moles
Ba(OH)₂:
0,0500L×0,10M = 0,005moles
The heat produced is:
0,005mol×-118 kJ/mol = -0,59 kJ = -590 J
The temperature increasing is:
Q = -C×m×ΔT
Where Q is heat (-590 J), m is mass of solution (100mL = 100g -density of 1,00g/mL) and ΔT is change in temperature.
Replacing:
-590J = -4,184J/g°C×100g×ΔT
<em>ΔT = 1,41°C</em>
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I hope it helps!
