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Alinara [238K]
3 years ago
14

Which process occurs at the anode in an electrochemical cell?

Chemistry
1 answer:
Fiesta28 [93]3 years ago
5 0

The process that occurs at the anode in an electrochemical cell is the loss of electrons. The answer is number 2. Oxidation occurs as electrons are lost at the anode at one of the electrodes in both an electrolytic cell and a voltaic cell.

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Which property describes a mixture? It cannot be separated by physical methods. It has a single chemical composition. It cannot
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it cannot be separated by physical methods

Explanation:

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What is the mass percent of potassium sulfate in solution if 78g of potassium sulfate is dissolved in 500 mL of water? (The dens
Debora [2.8K]

Answer:

13.5 %

Explanation:

First we<u> calculate the mass of 500 mL of water</u>, using <em>its density</em>:

  • Volume * Density = Mass
  • 500 mL * 1.00 g/mL = 500 g

Then we <u>calculate the mass percent of potassium sulfate</u>, using the formula:

Mass of Potassium Sulfate / Total Mass * 100%

  • 78 g / (78 + 500) g * 100 % = 13.5 %

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What is the first step of a ladybug during the growth and development process​
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7 0
3 years ago
In an electroplating process, copper (ionic charge +2e, atomic weight 63.6 g/mol) is deposited using a current of 10.0 A. What m
salantis [7]

Answer : The mass of copper deposit is, 1.98 grams

Explanation :

First we have to calculate the charge.

Formula used : Q=I\times t

where,

Q = charge = ?

I = current = 10 A

t = time = 10 min = 600 sec      (1 min = 60 sec)

Now put all the given values in this formula, we get

Q=10A\times 600s=6000C

Now we have to calculate the number of atoms deposited.

As, 1 atom require charge to deposited = 2\times (1.6\times 10^{-19})  

Number of atoms deposited = \frac{(6000)}{2\times(1.6\times 10^{-19})}=1.875\times 10^{22} atoms

Now we have to calculate the number of moles deposited.

Number of moles deposited = \frac{(1.875\times 10^{22})}{(6.022\times 10^{23})}=0.03113 moles

Now we have to calculate the mass of copper deposited.

1 mole of Copper has mass = 63.5 g  

Mass of Copper Deposited = 63.5\times 0.03113 =1.98g

Therefore, the mass of copper deposit is, 1.98 grams

5 0
3 years ago
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