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Lerok [7]
3 years ago
12

Your teacher gives you a sample of an unknown element which is sealed in a glass tube at room temperature. At the bottom of the

tube there is a small amount, a few drops at the most, of a red-black filmy liquid, and above it is a red vapor. What is this element likely to be?.
Chemistry
1 answer:
Nat2105 [25]3 years ago
7 0

The element is likely to be metal.

The substances that are pure and only consists of atoms are called elements. They are the smallest and the fundamental unit of the compound and cannot be split to form any entity.

<h3>What are metals?</h3>

The metals are the elements that are good conductors of charge, electricity, are opaque, malleable, lustrous and ductile.  They have high density and melting points. They differ from the non-metals and metalloids based on their physical and chemical properties.

The metals are more likely to donate and gain electrons to form complexes and can produce transitions. The electron gets excited when the energy is given in the form of heat and electricity and thus when comes to the ground state gives a distinct colouration.

Therefore, the element is likely to be metal.

Learn more about metals here:

brainly.com/question/24911138

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3 years ago
In the equation CH4 + 2O2 --&gt; 2H2O + CO2 What is the mass of CO2 produced when 35g of O2 reacts?
Anestetic [448]

Answer:

24.06 g of CO₂

Explanation:

The balanced equation for the reaction is given below:

CH₄ + 2O₂ —> 2H₂O + CO₂

Next, we shall determine the mass of O₂ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 2 × 32 = 64 g

Molar mass of CO₂ = 12 + (2×16)

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= 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

64 g of O₂ reacted to produce 44 g of CO₂.

Finally, we shall determine the mass of CO₂ produced by the reaction of 35 g of O₂. This can be obtained as follow:

From the balanced equation above,

64 g of O₂ reacted to produce 44 g of CO₂.

Therefore, 35 g of O₂ will react to produce = (35 × 44)/64 = 24.06 g of CO₂.

Thus, 24.06 g of CO₂ were produced from the reaction.

8 0
3 years ago
Ammonium Phosphate (NH4)3PO4 is a strong electrolyte. What will be the concentration of all the ions in a 0.9 M solution of ammo
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NH_4^+

<span>per 1 mole of salt and 1 mole of

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Explanation: I hope this helps!

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