One example of a solution<span> is </span>salt water<span> which is a </span>mixture<span> of </span>water<span> and </span>salt<span>. You cannot see </span>the salt<span> and </span>the salt<span> and </span>water<span> will stay a </span>solution<span> if left alone. Parts of a</span>Solution<span>. Solute - The solute is the substance that is being </span>dissolved<span> by another substance.</span>
Answer:
Explanation:
A is the correct answer.
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Relationship between [H3O+] and [OH-] is:
[H3O+] X [OH-] = 1.00 X10^-14
Rearranging gives:
[H3O+] = 1.0X10^-14 / [OH-]
Just plug in and calculate your [H3O+] values
Answer:
1.05 L
Explanation:
There is some info missing I think this is the original question.
<em>A laboratory experiment requires 250 millimeters of water boiling. it also requires 100 mills of water for a cooling process. If a student performs the experiment three times, how much total water will the student need? Give your answer in liters.</em>
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Step 1: Calculate the volume required for each experiment.
The volume required is the sum of the volumes used: 250 mL + 100 mL = 350 mL
Step 2: Calculate the volume required for the 3 experiments
We have to multiply the volume required for each experiment by 3.
3 × 350 mL = 1050 mL
Step 3: Convert the volume to liters
We use the relation 1 L = 1000 mL.
1050 mL × (1 L/1000 mL) = 1.05 L