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Softa [21]
3 years ago
9

1. If 100 mL of a gas, originally at 760 torr, is compressed to a pressure of 120 kPa

Chemistry
1 answer:
marshall27 [118]3 years ago
3 0

Answer : The final volume will be, 84.4 mL

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = 760 torr

P_2 = final pressure = 120 kPa = 900 torr   (1 kPa = 7.5 torr)

V_1 = initial volume = 100 mL

V_2 = final volume = ?

Now put all the given values in the above equation, we get:

760torr\times 100mL=900torr\times V_2

V_2=84.4mL

Therefore, the final volume will be, 84.4 mL

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Answer:

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Explanation:

Given parameters:

Partial pressure of gas 1 = 0.35atm

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Solution:

To solve this problem, we need to recall and understand the Dalton's law of partial pressure.

Dalton's law of partial pressure states that "the total pressure of a mixture of gases is equal to the sum of the partial pressure of the constituent gases".

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Now we substitute;

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8 0
3 years ago
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Answer:

The answer to your question is 4

Explanation:

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Learn more about The reactants here:- brainly.com/question/6421464

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