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Alex Ar [27]
2 years ago
10

which of the following polynomials has a graph with odd symmetry? a. 7x^4+13x^3-11 b. 5x^7+4x^6+3x^5+x c.13x^5 -1/2x^3+7x+3 d. 8

x^5+7x^3-5x
Mathematics
2 answers:
agasfer [191]2 years ago
6 0

Answer: 45x3x345!3

Step-by-step explanation:

you multiply all numbers then you divide by all the numbers there and there’s your answer

Zina [86]2 years ago
5 0

Answer:

D) f(x)=8x^5+7x^3-5x

Step-by-step explanation:

A function is odd if its graph is symmetric to the origin, which we can check this if f(-x)=-f(x) is true:

<u>Option A</u>

f(x)=7x^4+13x^3-11\\\\f(-x)=7(-x)^4+13(-x)^3-11\\\\f(-x)=7x^4-13x^3-11

Since f(-x)\neq-f(x), then the function does not have odd symmetry

<u>Option B</u>

<u />f(x)=5x^7+4x^6+3x^5+x\\\\f(-x)=5(-x)^7+4(-x)^6+3(-x)^5+x\\\\f(-x)=-5x^7+4x^6-3x^5+x

Since f(-x)\neq-f(x), then the function does not have odd symmetry

<u>Option C</u>

<u />f(x)=13x^5-\frac{1}{2}x^3+7x+3\\\\f(-x)=13(-x)^5-\frac{1}{2}(-x)^4+7(-x)+3\\ \\f(-x)=-13x^5-\frac{1}{2}x^4-7x+3

Since f(-x)\neq-f(x), then the function does not have odd symmetry

<u>Option D</u>

<u />f(x)=8x^5+7x^3-5x\\\\f(-x)=8(-x)^5+7(-x)^3-5(-x)\\\\f(-x)=-8x^5-7x^3+5x

Since f(-x)=-f(x), then the function DOES have odd symmetry. You can also see that the function is odd because every term has an odd exponent.

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