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DerKrebs [107]
2 years ago
6

Select all the correct answers. Why do real gases not behave exactly like ideal gases? Real gases are always hotter than ideal g

ases. Real gas particles have significant volume. Real gas particles have perfectly elastic collisions. Real gas particles are smaller than ideal gas particles. Real gas particles have more complex interactions than ideal gas particles.
Chemistry
1 answer:
Lemur [1.5K]2 years ago
4 0

Answer:

See below.

Explanation:

1. Real gases have significant volume.

2. Real gases have more complex interactions than ideal gases.

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How much heat energy, in kilojoules, is required to convert 72.0 gg of ice at −−18.0 ∘C∘C to water at 25.0 ∘C∘C ? Express your a
Ghella [55]

Answer: The enthalpy change is 34.3 kJ

Explanation:

The conversions involved in this process are :

(1):H_2O(s)(-18^0C)\rightarrow H_2O(s)(0^0C)\\\\(2):H_2O(s)(0^0C)\rightarrow H_2O(l)(0^0C)\\\\(3):H_2O(l)(0^0C)\rightarrow H_2O(l)(25^0C)

Now we have to calculate the enthalpy change.

\Delta H=[m\times c_{s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{l}\times (T_{final}-T_{initial})]

where,

\Delta H = enthalpy change = ?

m = mass of water = 72.0  g

c_{s} = specific heat of ice = 2.09J/g^0C

c_{l} = specific heat of liquid water = 4.184J/g^0C

n = number of moles of water = \frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{72.0g}{18g/mole}=4.00moles

\Delta H_{fusion} = enthalpy change for fusion = 6010 J/mole

Now put all the given values in the above expression, we get

\Delta H=[72.0g\times 2.09J/g^0C\times (0-(-18)^0C]+4.00mole\times 6010J/mole+[72.0g\times 4.184J/g^)C\times (25-0)^0C]\Delta H=34279.8J=34.3kJ        (1 KJ = 1000 J)

Therefore, the enthalpy change is 34.3 kJ

5 0
2 years ago
How does an earthquake cause a tsunami?
SSSSS [86.1K]
Yes because the earth plates are grinding against each other and are the main cause of Tsunami!
3 0
3 years ago
Read 2 more answers
How many milliliters of a 0.266 m lino3 solution are required to make 150.0 ml of 0.075 m lino3 solution?
Allisa [31]

We need an equation that would relate the concentration of the original solution to that of the desired solution. To solve this we use the equation expressed as follows, 

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

M1V1 = M2V2

0.266 M x V1 = 0.075 M x 150 mL

V1 = 42.29 mL


Therefore, we need about 42.29 mL of the 0.266 M of lithium nitrate solution to make 150.0 mL of the 0.075 M lithium nitrate solution.

3 0
3 years ago
Read 2 more answers
Calculate the wavelength of a football (425g) thrown by an NFL quarterback traveling at 50mph
AnnyKZ [126]

Wavelength is 6.976 x 10^ -35 m

Explanation:

In this, we can use De Broglie’s equation. This equation is the relationship between De Broglie’s wavelength, velocity and the mass of a moving object. In this equation, we are using plank's constant which is 6.626 x 10^-34 m^2 kg/s.

We know that one mile per hour is equivalent to 0.447 M/S.

And One gram is equivalent to 10^-3 kg.

De Broglie’s wavelength = λ ( wave length) = Plank’s constant/ Mass x velocity

λ ( wave length) = 6.626 x 10^ -34/ (425 x10^-3) x ( 50 x 0.447)

                                 = 6.626 x 10^ -34/ 0. 425 x 22.35

                                 = 6.626 x 10^ -34/ 9.498

                                 = 6.976 x10^ -35 m

So, the wavelength of the football will be 6.976 x 10^ -35 m

7 0
3 years ago
Balance the equation<br> N2O5 + H2 -&gt; NH3 + H2O
Lubov Fominskaja [6]

Answer:

I hope this is it. I'm not really sure.

4 0
2 years ago
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