The balanced chemical reaction are as follows:
<span>P8 + 5O2 --> 2P4O10
We are given the amount of P8 to be used in the reaction. We use this to calculate what is asked. We do as follows:
1.6 mol P8 ( 2 mol P2O10 / 1 mol P8 ) ( 283.89 g / mol ) = 908.45 g P4O10 produced</span>
Answer:
153.6771 amu
Explanation:
From the question given above, the following data were:
Isotope A:
Mass of A = 114.3789 amu
Abundance (A%) = 64.23%
Isotope B:
Mass of B =.?
Abundance (B%) = 100 – A%
Abundance (B%) = 100 – 64.23
Abundance (B%) = 35.77%
average atomic mass of Element Y = 128.4359 amu
The mass of the 2nd isotope (i.e isotope B) can be obtained as follow:
Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
128.4359 = [(114.3789 × 64.23)/100] + [(Mass of B × 35.77) /100]
128.4359 = 73.4656 + (Mass of B × 0.3577)
Collect like terms
128.4359 – 73.4656 = Mass of B × 0.3577
54.9703 = Mass of B × 0.3577
Divide both side by 0.3577
Mass of B = 54.9703 / 0.3577
Mass of B = 153.6771 amu
Therefore, the mass of the 2nd isotope is 153.6771 amu
Explanation:
i believe you meant particles*
The charge on Calcium is +2. Since, Calcium oxide is a neutral compound, so the charge on Oxygen should be -2. <span>Valency of Oxygen is 2, so a single Oxygen atom can satisfy the need.
Therefore, formula is CaO.</span>
I’ll get back to u on this
