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2 years ago

10

The temperature at which a substance in the liquid phase transforms to the gaseous phase refers to the substance's _______. A. s

ublimation point B. boiling point C. melting point D. freezing point

2 answers:

murzikaleks [220]2 years ago

3 0

When a substance goes from being a liquid to a gas it evaporates, or boils away. Think of boiled eggs.

JulijaS [17]2 years ago

3 0

It is the boiling point

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Which ocean surface current travels north along the eastern United States coast? A. Labrador current B. Canaries current C. Gulf

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3 years ago

Read 2 more answers

9. A tank truck carries 34 000 L of sulfuric acid. The density

creativ13 [48]

Answer:

<h2>62,560 kg</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question

volume = 34,000 L

density = 1.84 kg/L

We have

mass = 1.84 × 34,000 = 62,560

We have the final answer as

<h3>62,560 kg</h3>

Hope this helps you

7 0

2 years ago

How do I do question number 3? And what is the answer?

shutvik [7]

Answer:

60.02 g.

Explanation:

It is clear from the balanced equation:

<em>Mg + 2HCl → MgCl₂ + H₂. </em>

that 1.0 mole of Mg reacts with 2.0 moles of HCl to produce 1.0 mole of MgCl₂ and 1.0 moles of H₂.

20.0 g of Mg reacts with excess HCl. To calculate the no. of grams of HCl that reacted, we should calculate the no. of moles of Mg:

<em>no. of moles of Mg = mass/atomic mass</em> = (20.0 g)/(24.3 g/mol) = 0.823 mol.

From the balanced equation; every 1.0 mol of Mg reacts with 2 moles of HCl.

∴ 0.833 mol of Mg will react with (2 x 0.833 mol = 1.646 mol) of HCl.

<em>∴ The mass of reacted HCl = no. of moles x molar mass</em> = (1.646 mol)(36.46 g/mol) = <em>60.02 g.</em>

3 0

3 years ago

12. The vapor pressure of water at 90°C is 0.692 atm. What is the vapor pressure (in atm) of a solution made by dissolving 3.68

luda_lava [24]

Answer : The vapor pressure (in atm) of a solution is, 0.679 atm

Explanation : Given,

Mass of $H_2O$ = 1.00 kg = 1000 g

Moles of $CsF$ = 3.68 mole

Molar mass of $H_2O$ = 18 g/mole

Vapor pressure of water = 0.692 atm

First we have to calculate the moles of $H_2O$ .

$\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{1000g}{18g/mole}=55.55mole$

Now we have to calculate the mole fraction of $H_2O$

$\text{Mole fraction of }H_2O=\frac{\text{Moles of }H_2O}{\text{Moles of }H_2O+\text{Moles of }CsF}=\frac{55.55}{55.55+3.68}=0.938$

Now we have to partial pressure of solution.

According to the Raoult's law,

$P_{Solution}=X_{H_2O}\times P^o_{H_2O}$

where,

$P_{Solution}$ = vapor pressure of solution

$P^o_{H_2O}$ = vapor pressure of water = 0.692 atm

$X_{H_2O}$ = mole fraction of water = 0.938

$P_{Solution}=X_{H_2O}\times P^o_{H_2O}$

$P_{Solution}=0.938\times 0.692atm$

$P_{Solution}=0.649atm$

Therefore, the vapor pressure (in atm) of a solution is, 0.679 atm

5 0

2 years ago