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Alinara [238K]
3 years ago
6

What is the Value of the Median?

Mathematics
1 answer:
OlgaM077 [116]3 years ago
8 0

Answer:

The median is 4. It can be identified by the number under the line on the diagram.

Hope this helps!


Step-by-step explanation:


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Hello, can you please help me I need to write an expression for this word problem
Fudgin [204]
4•(-24)-3 You don't need any parenthesis because it's order of operations
5 0
3 years ago
Which triangles are congruent? How do you know?
choli [55]
Use the side lengths! C and D have lengths of 3 and heights of 4.
Also use how far away they are from the axis.

Both C and D are 2 away from each axis on the end point.
This also goes with A.
However, B does not seem to be congruent in the sense of (coordinates)
It is the same length and height.
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Solve the equation thanks!
AlladinOne [14]

Answer:

c = \frac{27}{40}

Step-by-step explanation:

To eliminate the fractions, multiply all terms by the lowest common multiple of 8 and 5

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5 + 40c = 32 ( subtract 5 from both sides )

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The midpoint of chord AB is ( , ), and the slope of chord AB is
kykrilka [37]

Answer:

See solution below

Step-by-step explanation:

Let the coordinate's of A and B be (1, 0) and (2,4) respectively

midpoint M (X, Y) = [(x1+x2/2, y1+y2/2)]

X = x1+x2/2

X = 1+2/2

X = 3/2

X = 1.5

Y = y1+y2/2

Y = 0+4/2

Y = 4/2

Y = 2

Hence the required midpoint (X, Y) is (1.5, 2)

Slope m = y2-y1/x2-x1

m = 4-0/2-1

m = 4/1

m = 4

Hence the slope is 4

<em>Note that the coordinates are assumed but the same calculation can be employed for any other coordinates</em>

7 0
3 years ago
Determine whether the relationship is an inverse variation or not. Explain.
kolbaska11 [484]

Answer: The product xy is not constant, so the relationship is not an inverse variation.

Step-by-step explanation:

For it to be an inverse variation, the product of x and y must be constant.

  • For the first row, xy=2(424)=848.
  • For the second row, xy=3(280)=840.
  • For the third row, xy=4(210)=840.

This means <u>the product xy is not constant, so the relationship is not an inverse variation.</u>

8 0
2 years ago
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