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3 years ago

14

Mike read 1/4 of the newspaper in 1/3 of an

1 answer:

gavmur [86]3 years ago

8 0

An hour and twenty minutes

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12) As of August, 2011, Russia has had 21 rocket launch failures out of 743 total launches. To the nearest whole number, how man

bogdanovich [222]

Answer:

23

Step-by-step explanation:

It is given that, in Russia there are 21 rocket launch failures out of 743 total launches. We need to find no of failures for the next 800 launches.

21 rocket = 743 launches

1 launch = $\dfrac{21}{743}\ \text{failures}$

For 800 launches,

$=\dfrac{21}{743}\ \text{failures}\times 800\\\\=22.611\ \text{failures}$

or

= 23 failures

So, there are 23 failures in next 800 launches.

5 0

3 years ago

The standard ratio of a photo's width to it's length is 2/3. what is the length of a photo that has a width of 14 inches?

ankoles [38]

L: w

Equation

2/3 = 14/ x

Cross multiply

2xX = 14x3

2x = 42

Eliminate

2x/2 = 42/2

X = 21

5 0

3 years ago

Read 2 more answers

How do you answer this and please show work if you solve?

nikklg [1K]

To solve this, simply switch the X and y variables within one equation, and upon doing so, see and check if it equals to the other equation.

f(X) = -X + 4/5
Y = -X + 4/5
X = (-Y+4)/5
5X = -Y + 4
-Y = 5X - 4
Y = -5x + 4

Yes, by looking at the second equation it is an inverse of the first one.

7 0

3 years ago

A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners

Vlada [557]

Answer:

The measures of the angles at its corners are $59.1\°,35.4\°,85.5\°$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

$185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)$

$2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}$

$cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))$ $cos(A)=0.513953$

$A=arccos(0.513953)=59.1\°$

step 2

Find the measure of angle B

Applying the law of cosines

$125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)$

$2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}$

$cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))$ $cos(B)=0.81489$

$B=arccos(0.81489)=35.4\°$

step 3

Find the measure of angle C

Applying the law of cosines

$215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)$

$2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}$

$cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))$ $cos(C)=0.0784$

$C=arccos(0.0784)=85.5\°$

3 0

3 years ago

In the year 1990, a total of 320 points were scored in a basketball game between the golden state warriors and the Denver nugget

liberstina [14]

6 points per minute

3 0

3 years ago