Solve for x: X/2=8 A)x=17 B)x=18 C)x=16 D)x=12

Mathematics

2 answers:

Yuki888 [10]3 years ago

7 0

The answer is C)x=16

poizon [28]3 years ago

3 0

If we are dividing than it would be answer C because 8x2=16 and 16/2=8

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Solve for W: P=2L + 2W<br><br>A. W=P-L<br>B. W= 1/2P - L<br>C. W= 1/2 P + L<br>D. W= 2P - L

svetlana [45]

Answer:

Step-by-step explanation:

$P=2L+2W$

$P-2L=2W$ (Subtract 2L from both sides of the equation)

$2W=P-2L$ (Symmetric Property of Equality)

$W=\frac{P-2L}{2}$ (Divide both sides of the equation by 2)

$W=\frac{P}{2} -\frac{2L}{2}$ ("Split" the fractions)

$W=\frac{1}{2}P-L$ (Simplify)

Hope this helps!

4 0

2 years ago

The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims

kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is $\mu=600$ , we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it $\sigma$ ) is

$\sigma=48$

Next they draw a random sample of n=70 students, and they got a mean score (denoted by $\bar x$ ) of $\bar x=613$

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis $H_0:\bar x \geq \mu$

- The alternative would be then the opposite $H_0:\bar x < \mu$

The test statistic for this type of test takes the form

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}$

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\$

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>