The telescope has the ability to enlarge an image and depends on the combination of lenses used.
Explanation:
Eyepiece performs magnification. The size of primary lens or primary mirror determines the Light gathering power. The main functions of telescope are light gathering, resolution and magnification.
The light gathering power has the ability of a telescope to collect more light than human eye. The purpose of telescope is to focus photons.
Answer:
0.5429 m/s^2
Explanation:
velocity of waterjet = 18 m/s
diameter of water jet ( d ) = 4 cm = 0.04 m
mass of vertical plate(m) = 750 kg
<u>Determine the acceleration of plate when the jet first strikes ( i.e. t = 0 )</u>
first we will determine the impact force
F = β*A*V^2 ----- ( 1 )
where ; β = 1000 kg/m^3 , A = π/4 * d^2 , V = 18 m/s
input values into equation 1
F = 407.15 N
<em>finally determine the acceleration at t = 0 </em>
F = m*a
a = F / m = 407.15 / 750 = 0.5429 m/s^2
Because it is how fast it goes and it depends on the speed
Answer:
(a) 0.177 m
(b) 16.491 s
(c) 25 cycles
Explanation:
(a)
Distance between the maximum and the minimum of the wave = 2A ............ Equation 1
Where A = amplitude of the wave.
Given: A = 0.0885 m,
Distance between the maximum and the minimum of the wave = (2×0.0885) m
Distance between the maximum and the minimum of the wave = 0.177 m.
(b)
T = 1/f ...................... Equation 2.
Where T = period, f = frequency.
Given: f = 4.31 Hz
T = 1/4.31
T = 0.23 s.
If 1 cycle pass through the stationary observer for 0.23 s.
Then, 71.7 cycles will pass through the stationary observer for (0.23×71.7) s.
= 16.491 s.
(c)
If 1.21 m contains 1 cycle,
Then, 30.7 m will contain (30.7×1)/1.21
= 25.37 cycles
Approximately 25 cycles.
Answer:
The current in the motor in this case is 13.2 A
Explanation:
Given:
Resistance 5 Ω
Emf V
Induced emf V
When motor run at half speed due to load increased then induced emf is also reduced to half of its value
So new induced emf in our case is given by,
V
Where
A
Therefore, the current in the motor in this case is 13.2 A