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marta [7]
3 years ago
11

If the temperature of the metal oxide and water solution is increased,this would most likely..

Physics
1 answer:
kiruha [24]3 years ago
7 0
Chemical Reaction between metal oxide and water solution
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A wave traveling in water has a frequency of 250 Hz and a wavelength of 6.0m. What is the speed of the wave?
vladimir2022 [97]
Since you are looking for the speed, you need to rearrange the formula which is f = speed / wavelength. That should give you speed = f (wavelength.) All you need to do next is to substitute the value to the following equation.  speed = 250 Hz (6.0m) that should leave you with 1500 m/s which is very fast.
6 0
3 years ago
A particle's position is given by z(t) = −(6.50 m/s2)t2k for t ≥ 0. (Express your answer in vector form.) a. Find the particle's
blondinia [14]

Answer:

a) z'(t) =v(t) = -13t

Now we can replace the velocity for t=1.75 s

v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}

For t = 3.0 s we have:

v(3.0s) = -13*3.0 =-39 \frac{m}{s}

b) v_{avg}= \frac{z_f - z_i}{t_f -t_i}

And we can find the positions for the two times required like this:

z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m

z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m

And now we can replace and we got:

V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}

Explanation:

The particle position is given by:

z(t) = -(6.5 \frac{m}{s^2}) t^2, t\geq 0

Part a

In order to find the velocity we need to take the first derivate for the position function like this:

z'(t) =v(t) = -13t

Now we can replace the velocity for t=1.75 s

v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}

For t = 3.0 s we have:

v(3.0s) = -13*3.0 =-39 \frac{m}{s}

Part b

For this case we can find the average velocity with the following formula:

v_{avg}= \frac{z_f - z_i}{t_f -t_i}

And we can find the positions for the two times required like this:

z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m

z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m

And now we can replace and we got:

V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}

8 0
3 years ago
How does upwelling affect the weather of a coastal region?
SIZIF [17.4K]

c.The warm surface water results in moist air and more rainfall.

Explanation:

  • During upwelling, cold water in the ocean is stirred up and brought to the surface.
  • The warmer surface water is then taken into deeper parts of the ocean.
  • Upwelling allows for nutrient mixing in the ocean and allows for useful gases to circulate well.
  • The warm surface water causes the air to be moisty.
  • When the air is carried landward towards the coast, it leads to rainfall when the saturated air releases the water.
  • The air then becomes cold and dry and it rises up.
  • Therefore, warm surface water results in moist air and more rainfall.

Learn more:

Ocean current brainly.com/question/4117397

#learnwithBrainly

4 0
3 years ago
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Investigate the relationship between volume and pressure of a gas at a constant temperature.
sveta [45]
Gay Lussac's Law states: At a constant volume Pressure<span> divided by </span>Temperature<span> is</span>constant<span> P/T = k Together these three laws form the foundation of the Ideal </span>Gas<span>Law. Objective: Students will </span>investigate<span> Gay Lussac's Law relating </span>pressure<span> and</span>temperature<span> at a </span><span>constant temperature.</span>
7 0
3 years ago
The mass of the Earth is 5.972 × 10^27 g. Convert this mass to kg.
sineoko [7]

Answer:

5.972x10^27 x 10^-3 = 5.972x10^24

Explanation:

1g = 10^-3 kg => So the mass of Earth in kg is 5.972x10^24

3 0
3 years ago
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