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Mila [183]
3 years ago
14

What is mass? A. the force on an object caused by gravity B. the amount of space that something takes up C. the amount of matter

in an object D. how fast something is moving
Chemistry
1 answer:
Kisachek [45]3 years ago
7 0

the answer should be A. :)

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What might have caused this canyon to form
Klio2033 [76]

Answer:

Explanation:

Canyons form through processes of erosion, although in a few instances they can be caused by the movement of tectonic plates. A canyon starts out as a riverbed, and over centuries of time, the river cuts more and more deeply into the rock, creating a deep gorge.

6 0
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Boys and girls are often encouraged to play different sports <br> true or false
Elanso [62]
In society today, I’d say T
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Determine the percent composition of Ca3(PO4)2
Tamiku [17]

determine the percent of composition

8 0
4 years ago
Is 2 C4H10 + 13 O2 → 8 CO2 + 10 H2O a double replacement?
natulia [17]

Answer:

The answer to your question is No, it is not.

Explanation:

Data

                C₄H₁₀  +  13O₂   ⇒   8CO₂ +  10H₂O

In a double replacement reaction, two reactants interchange cations an example of these reactions are neutralization reactions. In neutralization reactions, an acid and a base react to form a salt and water.

The reaction of this problem is not a double replacement reaction because the products are carbon dioxide and water, not a salt and water.

The reaction of this problem is a combustion reaction.

8 0
4 years ago
If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution
Helen [10]

This is a straightforward dilution calculation that can be done using the equation

M_1V_1=M_2V_2

where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

M_2=\frac{M_1V_1}{V_2}.

Substituting in our values, we get

\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

5 0
3 years ago
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