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3 years ago

Is 2 C4H10 + 13 O2 → 8 CO2 + 10 H2O a double replacement?

Chemistry

1 answer:

natulia [17]3 years ago

8 0

Answer:

The answer to your question is No, it is not.

Explanation:

Data

C₄H₁₀ + 13O₂ ⇒ 8CO₂ + 10H₂O

In a double replacement reaction, two reactants interchange cations an example of these reactions are neutralization reactions. In neutralization reactions, an acid and a base react to form a salt and water.

The reaction of this problem is not a double replacement reaction because the products are carbon dioxide and water, not a salt and water.

The reaction of this problem is a combustion reaction.

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For each of the acid–base reactions, calculate the mass (in grams) of each acid necessary to completely react with and neutraliz

LiRa [457]

Acid-base neutralization reaction is defined as reaction of acid with base to form corresponding salt and water. Strong acid and base completely neutralize each other.

(a) The acid base neutralization reaction is as follows:

$HCl(aq)+NaOH(aq)\rightarrow H_{2}O(l)+NaCl(g)$

From the above balanced chemical reaction, 1 mol of NaOH completely reacts with 1 mol of HCl. The mass of NaOH is given 4.85 g, convert this into number of moles as follows:

$n=\frac{m}{M}$

Molar mass of NaOH is 39.997 g/mol, thus,

$n=\frac{4.85 g}{39.997 g/mol}=0.121 mol$

Thus, 0.121 mol of NaOH reacts with same amount of HCl and number of moles of HCl will be 0.121 mol.

Since. molar mass of HCl is 36.46 g/mol, thus, mass can be calculated as follows:

$m=n\times M=0.121 mol\times 36.46 g/mol=4.421 g$

Therefore, 4.421 g of HCl completely reacts with 4.85 g of NaCl.

(b) The acid base neutralization reaction is as follows:

$2HNO_{3}(aq)+Ca(OH)_{2}(aq)\rightarrow 2H_{2}O(l)+Ca(NO_{3})_{2}(aq)$

From the above balanced chemical reaction, 1 mol of $Ca(OH)_{2}$ completely reacts with 2 mol of $HNO_{3}$ . The mass of $Ca(OH)_{2}$ is given 4.85 g, convert this into number of moles as follows:

$n=\frac{m}{M}$

Molar mass of $Ca(OH)_{2}$ is 74.093 g/mol, thus,

$n=\frac{4.85 g}{74.093 g/mol}=0.06545 mol$

Thus, 0.06545 mol of $Ca(OH)_{2}$ reacts with $2\times 0.06545 mol=0.13091 mol$ of $HNO_{3}$

Since. molar mass of $HNO_{3}$ is 63.01 g/mol, thus, mass can be calculated as follows:

$m=n\times M=0.13091 mol\times 63.01 g/mol=8.25 g$

Therefore, 8.25 g of $HNO_{3}$ completely reacts with 4.85 g of $Ca(OH)_{2}$ .

$H_{2}SO_{4}(aq)+2 KOH (aq)\rightarrow 2H_{2}O(l)+K_{2}SO_{4}(aq)$

From the above balanced chemical reaction, 2 mol of KOH completely reacts with 1 mol of $H_{2}SO_{4}$ . The mass of KOH is given 4.85 g, convert this into number of moles as follows:

$n=\frac{m}{M}$

Molar mass of KOH is 56.1056 g/mol, thus,

$n=\frac{4.85 g}{56.1056 g/mol}=0.0864 mol$

Thus, 0.0864 mol of KOH reacts with $\frac{0.0864 mol}{2}=0.0432 mol$ of $H_{2}SO_{4}$

Since. molar mass of $H_{2}SO_{4}$ is 98.079 g/mol, thus, mass can be calculated as follows:

$m=n\times M=0.0432 mol\times 98.079 g/mol=4.24 g$

Therefore, 4.24 g of KOH completely reacts with 4.85 g of $H_{2}SO_{4}$ .

8 0

3 years ago

Which tempature is warmer than the freezing point in water?

vfiekz [6]

Water freezes at 0°C, 32°F, and 273°K. The only temperature warmer than the freezing point is 1°C.

7 0

3 years ago

Read 2 more answers

Can synthetic chemicals have origins in nature, or are they completely man-made? Give examples and

Aneli [31]

Yes they can have origins in nature. A bunch of the elements on the periodic table are chemicals and this are basic substances and cannot be man made.

6 0

3 years ago

Which subatomic particle of an atom never changes?

AlexFokin [52]

Protons are one of the fully stable parts of matter

8 0

3 years ago

A 2.5 L container is filled with propane. The ambient temperature is 25°C and the

madam [21]

Answer:

The pressure inside the container will be 3.3 atmospheres

Explanation:

The relationship between the temperature and pressure of a gas occupying a fixed volume is given by Gay-Lussac's law which states that the pressure of a given amount of gas is directly proportional to its temperature on the kelvin scale when the volume is kept constant.

Mathematically, it expressed as: P₁/T₁ = P₂/T₂

where P₁ is initial pressure, T₁ is initial temperature, P₂ is final pressure, T₂ is final temperature.

The above expression shows that the ratio of the pressure and temperature is always constant.

In the given question, the gas in the can attains the temperature of its environment.

P₁ = 3 atm,

T₁ = 25 °C = (273.15 + 25) K = 298.15 K,

P₂ = ?

T₂ = (55 °C = 273.15 + 55) K = 328.15 K

Substituting the values in the equation

3/298.15 = P₂/328.15

P₂ = 3 × 328.15/298.15

P₂ = 3.3 atm

Therefore, the pressure inside the container will be 3.3 atmospheres

7 0

3 years ago