Answer:
62.586 gram
Explanation:
moles of Al(OH)3 = mass / molar mass = 35.1 / (27+17x3) = 0.45 mol
moles of H2SO4 = mass / molar mass = 53.94 / (2+32+16x4) = 0.55 mol
H2SO4 is the limiting reagent (reacts completely)
⇒ moles of Al2(SO4)3 is worked out by moles of H2SO4
moles of Al2(SO4)3 = moles of H2SO4 / 3 = 0.183 mol
mass of Al2(SO4)3 = mole x molar mass = 0.183 x (27x2 + 96x3) = 62.586 gram
Answer:
The first one is air the second is decreases the third is water the fourth is gas and the last is liquid.
Explanation:
Hope it helps.
Answer:
No it will not have the same chemical properties as the initial substance.
Explanation:
In a chemical change, the atoms in the reactants rearrange themselves and bond together differently to form one or more new products with different characteristics than the reactants
Mole ratio:
MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl
2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂
moles Mg(OH)₂ = 4 x 1 / 2
= 2 moles of Mg(OH)₂
molar mass Mg(OH)₂ = 58g/mol
mass of Mg(OH)₂ = n x mm
mass of Mg(OH)₂ = 58 x 2
= 116 g of <span> Mg(OH)₂</span>
hope this helps!
<span>SO3
for the formal charges, we have:
for the single-bonded oxygens F.C. = 6 - [1/2(2) + 6] = -1
for the double-bonded oxygen F.C. = 6 - [1/2(4) + 4] = 0
for the sulfur F.C. = 6 - [1/2(8) + 0] = 2
Again, the formal charges add to zero. The oxidation numbers of O and S are -2 and +6, respectively. Note the three resonance forms!</span>