All categories

3 years ago

Smoking marijuana can be as unhealthy as smoking cigarettes and ___________

2 answers:

8 0

Smoking marijuana can be as unhealthy as smoking cigarettes and A.Can cause cancer.

<span>♡♡Hope I helped!!! :)♡♡
</span>

Afina-wow [57]3 years ago

3 0

The answer is all of them. But in a school situation, A would be appropriate. This is because the smoke gets into the smokers lungs, whether it be marijuana or tobacco, and can cause cancer cells to grow in your lungs and enter your bloodstream.
So A is the answer.

You might be interested in

Identify and describe 2 changes of state that release energy

soldier1979 [14.2K]

Answer: All changes of state involve the transfer or energy

Explanation: i got my information from this site

https://www.esrl.noaa.gov/gmd/education/info_activities/pdfs/CTA_the_water_cycle.pdf

4 0

3 years ago

What is the molar mass of a gas which has a density of 0.00249 g/mL at 20.0 degrees celcius and 744.0 mm Hg?

creativ13 [48]

61.24 is the molar mass of a gas which has a density of 0.00249 g/mL at 20.0 degrees celcius and 744.0 mm Hg.

Explanation:

given that:

density = 0.00249 g/ml ( $\frac{mass}{volume}$ ) or 2.49 grams/litre

P = 744 mm Hg OR 0.978 atm

T = 20 Degrees or 293.15 Kelvin

R = 0.08206 Litre atm/mole K

molar mass =?

Formula used/

PV = nRT equation 1

here n is number of moles:

n = $\frac{mass}{atomic mass}$

putting the value of n and value of density in the equation 1:

PV = $\frac{mass}{molar mass}$ x RT

molar mass = $\frac{mass}{volume}$ x $\frac{RT}{P}$

= density x $\frac{RT}{P}$

= $\frac{2.49 x 0.08276 x 293.15}{0.978}$

= 61.24 is the molar mass of the gas.

8 0

3 years ago

Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the system,

gayaneshka [121]

Answer:

B > D > C > A

Explanation:

For the first law of the thermodynamics, the total energy variation in a process is:

ΔU = Q - W

Where Q is the heat, and W the work. If the system loses heat, Q < 0, if it absorbs heat, Q>0. If work is done in the system (volume decreases), W < 0, if the system does the work (volume increases), W > 0.

A. If the surroundings get colder, the system is absorbing heat, so Q>0, and the system decreases in volume so W < 0 :

ΔU = +Q - (-W) = +Q + W (absorbs a higher energy)

B. If the surroundings ger hotter, the system is losing heat, so Q<0, and the system expands, so W>0:

ΔU = -Q -W (loses higher energy)

C. Surroundings get hotter, Q<0, and the system decreases in volume, W<0

ΔU = - Q + W = 0 (magnitude of heat and work is similar)

D. Surroundings get hotter, Q<0, and the system is not changing in volume, W = 0.

ΔU = -Q (loses energy)

For the most released (more negative) for the most absorbed (most positive):

B > D > C > A

3 0

3 years ago

Which of the following forms of matter can be classified as being

Minchanka [31]

The answer is SOLUTIONS

6 0

3 years ago

What functional group is present in all carbohydrates? chemistry?

Oxana [17]

Carbohydrates contain a carbonyl group =C=O and hydroxyl groups -OH.

7 0

3 years ago