Answer:
13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.
Explanation:
Length of the base = l
Width of the base = w
Height of the pyramid = h
Volume of the pyramid = 
We have:
Rate at which water is filled in cube = 
Square based pyramid:
l = 6 cm, w = 6 cm, h = 13 cm
Volume of the square based pyramid = V





Differentiating V with respect to dt:




Putting, h = 4 cm


13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.
Answer:
The answer to your question is:
Explanation:
Other sugars with the same chemical formula as Glucose:
Sugar Formula Description
Glucose C₆H₁₂O₆ It's the most abundant monosaccharide.
Mannose C₆H₁₂O₆ It's found in plants and some animals.
Fructose C₆H₁₂O₆ It's the sugar of fruits.
Galactose C₆H₁₂O₆ It's found in milk.
Answer: 400K
Explanation:
Given that,
Original volume of balloon V1 = 3.0L
Original temperature of balloonT1 = 27°C
Convert the temperature in Celsius to Kelvin
(27°C + 273 = 300K)
New volume of balloon V2 = 4.0L
New temperature of balloon T2 = ?
Since volume and temperature are given while pressure is constant, apply the formula for Charle's law
V1/T1 = V2/T2
3.0L/300K = 4.0L/T2
To get the value of T2, cross multiply
3.0L x T2 = 4.0L x 300K
3.0LT2 = 1200LK
Divide both sides by 3.0L
3.0LT2/3.0L = 1200LK/3.0L
T2 = 400K
Thus, at a temperature of 400 Kelvin, the balloon would have a volume of 4.0L.
Explanation:
Element Abundance percent by weight Abundance parts per million by weight
Oxygen 46.1% 461,000
Silicon 28.2% 282,000
Aluminum 8.23% 82,300
Iron 5.63% 56,300
In such type of problems where reactant and product ratios are calculated one (Launa) should take start from balanced chemical equation. A balanced chemical equations helps in solving such problems. For this purpose chemical equation of this combustion reaction is drawn.
Equation:
C₃H₁₀ ⁺ 5 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 3 CO₂ ⁺ 4 H₂O
Now, According to this balanced equation one molecule of propane reacts with 5 molecules of oxygen to produce 3 molecules of carbon dioxide and 4 molecules of water.
As She is given with 2 molecules of propane and 10 molecules of oxygen, which means that the equation is multiplied by 2. So, the product side must also be multiplied by 2 to balance the equatio (Law of Conservation of Mass).
Result:
( C₃H₁₀ ⁺ 5 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 3 CO₂ ⁺ 4 H₂O ) ₓ 2
2 C₃H₁₀ ⁺ 10 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 6 CO₂ ⁺ 8 H₂O
So, 6 molecules of carbon dioxide and 8 molecules of water are produced.