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Ostrovityanka [42]
3 years ago
13

What factor affects both kinetic energy and gravitational potential energy?

Chemistry
2 answers:
Anna11 [10]3 years ago
8 0

Answer:

The kinetic energy of an object is also measured in joules. Anything that is moving has kinetic energy, but various factors affect how much kinetic energy an object has. The first factor is speed. If two identical objects are moving at different speeds, the faster object has more kinetic energy.  In physics, the kinetic energy  of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body when decelerating from its current speed to a state of rest.

Explanation:

katovenus [111]3 years ago
7 0

Answer: Potential energy is a little different. It is the energy an object has the potential to create. The energy produced is determined similarly to kinetic. It depends on the object's mass, the gravitational pull when up or down slopes, and the height of the reference point.

another explanation:

a) Potential Energy:

mass and height

We know that potential energy, PE is equal to the product of the mass, the gravitational acceleration and the height.

Since gravity is constant, the mass and height are the factors.

b) Kinetic Energy:

The mass (m) of the object and the speed (v) of the object.

Because kinetic energy is proportional to the velocity squared, increases in velocity will have an exponentially greater effect on transitional kinetic energy. Doubling the mass of an object will only double its kinetic energy, but doubling the velocity of the object will quadruple its velocity.

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Olenka [21]

As per Ideal gas equation, molar mass of the gas is 5.032 g/mo

We’ll begin by calculating the number of mole of the gas. This can be obtained as follow:

Volume (V) = 1.6 L

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According to Ideal gas equation , PV = nRT

0.92 × 1.6 = n × 0.0821 × 287

1.472 = n × 23.5627

Divide by 23.5627

n = 1.176 / 23.5627

n = 0.0624 mole

Finally, we shall determine the molar mass of the gas. This can be obtained as follow:

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Mole = \frac{mass}{molar mass}

0.0624 = \frac{0.314}{molar mass}

Cross multiply

0.0624 × molar mass of gas = 0.314

Divide by 0.0624

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Molar mass of gas = 5.032 g/mo

Therefore the Molar mass of gas is 5.032 g/mo

Learn more about  Ideal gas equation here:

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