NO.OF.MOLES= MASS/ATOMIC MASS
THE ATOMICITY OF SULPHUR IS 8 AND ITS MASS NUMBER IS 32.
SO, THE ATOMIC MASS IS 256
NO.OF.MOLES= 53.7/256
= 537/2560
= 0.2097
Humphry Davy First discovered sodium
Answer:
74.0 g/mol
Explanation:
Step 1: Write the generic neutralization reaction
HA + NaOH ⇒ NaA + H₂O
Step 2: Calculate the reacting moles of NaOH
At the equivalence point, 33.83 mL of 0.115 M NaOH react.
0.03383 L × 0.115 mol/L = 3.89 × 10⁻³ mol
Step 3: Calculate the moles of HA that completely react with 3.89 × 10⁻³ moles of NaOH
The molar ratio of HA to NaOH is 1:1. The reacting moles of HA is 1/1 × 3.89 × 10⁻³ mol = 3.89 × 10⁻³ mol.
Step 4: Calculate the molar mass of the acid
3.89 × 10⁻³ moles of HA have a mass of 0.288 g.
M = 0.288 g / 3.89 × 10⁻³ mol = 74.0 g/mol
Answer:
n = 6.06 x 
mol
Explanation:
n =?
m = 3.06 x 10-³ g
M (H5) = 5 x 1.01 (Since we only want hydrogen)
Atomic mass of C = 12.01
Atomic mass of H is 1,01, etc.
Having this data, we can use the Molar mass formula and change it so we can know the quantity of matter (n) in moles, and we just replace it.
M = 
⇔ n = 
⇔ n = 
⇔ n = 6.06 x mol
Note: The numbers I've used may be different from yours, by a small difference. I don't know if it's the case, but hope it helped.
