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marin [14]
3 years ago
5

I needed help with small numbers2 - 1003-10002-100004 1000000 each in standard form

Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0
10^1
10^2
10^3
10^4 
probably wrong

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11/16 on a number line that goes from 0-2
Dafna11 [192]

Answer:

is there a picture and if not its fine

7 0
3 years ago
For each $n \in \mathbb{N}$, let $A_n = [n] \times [n]$. Define $B = \bigcup_{n \in \mathbb{N}} A_n$. Does $B = \mathbb{N} \time
andre [41]

Answer:

No, it is not.

Step-by-step explanation:

The set C = \mathbb{N} \times \mathbb{N} contains every ordered pair of Natural numbers, while B only contains those pairs in which both values in each entry are the same. Therefore, C is a bigger set than B, but B is not equal to C because for example C contains [1] \times [2] and B doesnt because 1 is not equal to 2.

4 0
3 years ago
2) Two full revolutions = how many degrees? I
VARVARA [1.3K]

Answer:

720 degrees

Step-by-step explanation:

one full rotation is 360 degrees

360 + 360 = 720

5 0
4 years ago
Read 2 more answers
Th<br> Write an<br> explicit formula for<br> ans<br> then<br> term of the sequence 40,50,60, ....
kenny6666 [7]
<h3>Answer:   a_n = 10n+30</h3>

n starts at 1, and n is a positive whole number (1,2,3,...)

======================================================

Explanation:

The sequence is arithmetic with first term 40 and common difference 10. Meaning we add 10 to each term to get the next one.

--------

a1 = 40 = first term

d = 10 = common difference

a_n = a_1 + d(n-1)\\\\a_n = 40 + 10(n-1)\\\\a_n = 40 + 10n-10\\\\a_n = 10n + 30\\\\

is the general nth term of this arithmetic sequence

Plug in n = 1 and you should get a_1 = 40

Plug in n = 2 and you should get a_2 = 50

and so on

6 0
4 years ago
Show All Work
Angelina_Jolie [31]
The unit rate you're trying to find is pages per day(or p/d), so the equation needs to have both a unit for pages and for days.
The equation we have is:
5,249 = 29d
If they read 5,249 <em>pages</em>, then we can include the unit for pages in the equation.
Since we also know that <em>d</em> is the number of days it took, you can replace <em>d</em> with days.
The equation becomes:
5,249\ pages=29*(x\days)
Now that we have one variable, we can solve for <em>p/d</em>:
\frac{5,249\ pages}{29}=x\ days\\\\181 = x
Thus it took them 181 days to read it all.

If Johnny read 5,249 pages over 181 days and the unit rate is pages per day(p/d), then the equation for finding <em>p/d</em> is:
\frac{p\ pages}{d\ days}=\frac{5,249\ pages}{181\ days}=\frac{29\ pages}{1\ day}\\\\29\ \frac{pages}{day}
Johnny read 29 pages per day.
8 0
3 years ago
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