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DerKrebs [107]
3 years ago
9

An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel 1530 m/s in seawater. How deep is th

e water directly below the vessel if the time delay of the echo to the ocean floor and back is 7 s? Answer in units of m 039 10.0 points An example of stored chemical energy is:______
Physics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

a.  x=5355m   b. food

Explanation:

A wave is a disturbance wic travels through a medium, it transfers energy without the displacement of the medium itself.

the problem can be solved with this formula v

v=2x/t

v=speed of the ultrasonic wave in seawater

x=te distance between the seawater surface and the seawater bed

t=time it takes to travel to and fro te seawater bed to the surface

v= 1530 m/s,  t=7 s    , x=?

1530=2x/7

1530*7=2x

x=5355m

b. An example of stored h energy is food, petroleum etc.Chemical energy are Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat; called exothermic.

Reactions that require an input of heat to proceed may store some of that energy as chemical energy in newly formed bonds. we eat food so that we can h enough energy to carry out our day to day task.

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A tourist stands at the top of the Grand Canyon, holding a rock, overlooking the valley below. Find the final velocity and displ
Anestetic [448]

Answer:

a. -39.2 m/s; -78.4 m

b. -31.2 m/s; -46.4 m

c. -47.2 m/s; -110.4 m

Explanation:

<h2>Part (a)</h2>

We are given/can infer these variables:

  • t = 4.0 s
  • a = -9.8 m/s²
  • v_0 = 0 m/s

We want to find the displacement and the final velocity of the rock.

  • Δx = ?
  • v = ?

We can use this equation to find the final velocity:

  • v = v_0 + at

Plug in the known variables into this equation.

  • v = 0 + (-9.8)(4.0)
  • v = -9.8 * 4.0
  • v = -39.2 m/s

The final velocity of the rock is -39.2 m/s.

Now we can use this equation to find the displacement of the rock:

  • Δx = v_0 t + 1/2at²

Plug in the known variables into this equation.

  • Δx = 0 * 4.0 + 1/2(-9.8)(4.0)²
  • Δx = 1/2(-9.8)(4.0)²
  • Δx = -4.9 * 16
  • Δx = -78.4 m

The displacement of the rock is -78.4 m.

<h2>Part (b)</h2>

We are given/can infer these variables:

  • v_0 = 8.0 m/s
  • a = -9.8 m/s²
  • t = 4.0 s

We can use this equation to find the final velocity:

  • v = v_0 + at

Plug in the known variables into this equation.

  • v = 8.0 + (-9.8)(4.0)
  • v = 8.0 + -39.2
  • v = -31.2 m/s

The final velocity of the rock is -31.2 m/s.

We can use this equation to find the displacement:

  • Δx = v_0 t + 1/2at²

Plug in known variables:

  • Δx = 8.0(4.0) + 1/2(-9.8)(4.0)²
  • Δx = 32 - 4.9(16)
  • Δx = -46.4 m

The displacement of the rock is -46.4 m.

<h2>Part (c)</h2>

We are given/can infer these variables:

  • v_0 = -8.0 m/s
  • a = -9.8 m/s²
  • t = 4.0 s

We can use this equation to find the final velocity:

  • v = v_0 + at

Plug in the known variables into this equation.

  • v = -8.0 + (-9.8)(4.0)
  • v = -8.0 - 39.2
  • v = -47.2 m/s

The final velocity of the rock is -47.2 m/s.

We can use this equation to find the displacement:

  • Δx = v_0 t + 1/2at²

Plug in known variables:

  • Δx = -8.0(4.0) + 1/2(-9.8)(4.0)²
  • Δx = -32 - 4.9(16)
  • Δx = -110.4 m

The displacement of the rock is -110.4 m.

8 0
3 years ago
How does a valve cause a pressure drop in terms of the individual molecules in the liquid?
andre [41]
Opening the valve allows more of the pressurized material out. If the area is decreased, less of the pressurized material is released, and its force ends up more spread out, reducing the pressure. Opening the valve will increase volume of transfer of your liquid.
8 0
3 years ago
What does the doppler effect indicate about the motion of galaxies?
Taya2010 [7]
When galaxies move farther away the wavelength of the light is longer causing the galaxy to shift red but if it moves closer, the wavelength of the light gets smaller causing the galaxy to blue shift. The reason that the wavelength increases or decrease is due to the doppler effect.
8 0
3 years ago
An oil layer that is 5.0 cm thick is spread smoothly and evenly over the surface of water on a windless day. What is the angle o
Fofino [41]

Answer:

32.1

Explanation:

NOTE: You did not state the angle of incidence, and thus, I will be using 45° as my angle of incidence, all you need to do is replace it with your own value if it's different.

To solve this question, we are going to be using Snell's Law.

Snell's law describes the relationship between the angles of incidence and refraction, when referring to light or other waves passing through a boundary between two different isotropic media, such as water, glass, or air.

Snell's law is mathematically given as

sin(A1)/sin(A2) = n2/n1, where

n1 = incidence index

n2 = refracted index

A1 = incidence angle

A2 = refracted angle

The refraction index of oil is 1.15, and that of water is 1.33, so

if we take oil first,

sin A2 = (n1.sinA1)/n2

sin A2 = (1 * sin 45)/1.15

sin A2 = 0.7071/1.15

sin A2 = 0.6149

A2 = sin^-1 0.6149

A2 = 37.9°

Then

sin A3 = (1.15 * sin 37.9) / 1.33

sin A3 = (0.6149 * 1.15) / 1.33

sin A3 = 0.7071 / 1.33

sin A3 = 0.5317

A3 = sin^-1 0.5317

A3 = 32.1

4 0
3 years ago
The fastest measured pitched baseball left the pitcher's hand at a speed of 42.0 m/s. If the pitcher was in contact with the bal
I am Lyosha [343]

Answer:

The acceleration and time are 588 m/s² and 0.071 sec respectively.

Explanation:

Given that,

Speed = 42.0 m/s

Distance = 1.50 m

(a). We need to calculate the acceleration

Using equation of motion

v^2=u^2+2as

a=\dfrac{v^2-u^2}{2s}

Put the value in the equation

a=\dfrac{42.0^2-0}{2\times1.50}

a=588\ m/s^2

(b). We need to calculate the time

Using equation of motion

v = u+at

t=\dfrac{v-u}{a}

t=\dfrac{42.0-0}{588}

t=0.071\ sec

Hence, The acceleration and time are 588 m/s² and 0.071 sec respectively.

8 0
3 years ago
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