<span>False,
This is because when you can easily ionize and atom or the chances of it being ionizable are quite high, it means that that particular atom have very low ionization potential that is the reason why it was easily ionizable
An atom with a high ionization power and a firmly negative electron fondness will both pull in electrons from different particles and oppose having its electrons taken away; it will be an exceedingly electronegative molecule.</span>
Answer:
Mass = 9.58 g
Explanation:
Given data:
Mass of Zn = 2g
Theoretical yield of ZnI₂ = ?
Solution:
Chemical equation:
Zn + I₂ → ZnI₂
Number of moles of Zn:
Number of moles = mass/molar mass
Number of moles = 2g / 65.38 g/mol
Number of moles = 0.03 mol
Now we will compare the moles of Zn and ZnI₂.
Zn : ZnI₂
1 : 1
0.03 : 0.03
Mass of ZnI₂:
Mass = number of moles × molar mass
Mass = 0.03 mol × 319.22 g/mol
Mass = 9.58 g
Technically there is only one phase unless you account for a solution where you have a pure liquid with something dissolved in it. Unless you count aqueous as a phase which is just dissolved. Since you are in high school the answer you are looking for is one. <span />
<h3>
Answer:</h3>
3.5 Newton
<h3>
Explanation:</h3>
We are given;
Mass of the ball = 140 g
Acceleration = 25 m/s²
Required to find the force;
- According to Newton's second law of motion, the resultant force on a body in motion and the rate of change in linear momentum are directly proportional.
- That is;
- Thus; F = ma , where F is the resultant force, m is the mass and a is the acceleration.
To get the force we substitute the value of m and a in the formula;
Therefore;
F = 0.14 kg × 25 m/s²
= 3.5 N
Hence, the force needed to accelerate the ball is 3.5 N
Answer: 7.07 grams
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of 
require 1 mole of 
Thus 0.052 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 mole of give = 1 mole of 
Thus 0.052 moles of give = of
Mass of 
Thus 7.07 g of will be produced from the given masses of both reactants.
