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Amanda [17]
3 years ago
6

When a solid mixture of mgco3 and caco3 is heated strongly, carbon dioxide gas is given off and a solid mixture of mgo and cao i

s obtained. if a 24.00 g sample of a mixture of mgco3 and caco3 produces 12.00 g co2, then what is the percentage by mass of mgco3 in the original mixture? express your answer u?
Chemistry
1 answer:
just olya [345]3 years ago
8 0
MgCO3---> MgO +CO2  , x mol MgCO3       
M(MgCO3)=24.3+12.0+48.0=84.3 g/mol

CaCO3--->CaO+CO2   , y mol CaCO3   
M(CaCO3)=40.0+12.0+48.0=100g/mol     
M(CO2)=44.0

x*84.3 + y*100=24.00
x*44+y*44=12.00            x+y=12/44=0.2727, x=0.2727-y
(0.2727-y)*84.3 + y*100=24.00
22.99-84.3y+100y=24.00
22.99+15.7y= 24.00,     15.7y=1.01,    y=0.06430 mol CaCO3
x=0.2727-0.06430=0.2084 mol MgCO3
0.06430 mol CaCO3*100g/mol=6.43 g CaCO3
0.2084 mol MgCO3*84.3g/mol=17.57 g MgCO3
what does it mean express your answer u?



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Answer:

1)  <u>10.0 moles of NO</u>

<u>2) 25 moles of NaCl</u>

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<u>4) 1.03 moles of MgO</u>

<u>5) 0.72 moles H2</u>

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1. How many moles of nitrogen monoxide can be made using 5.0 moles of oxygen in the following composition reaction?

N2 + O2 → 2NO

For 1 mol N2 we need 1 mol O2 to produce 2 moles of NO

For 5.0 moles of N2 we need 5.0 moles of O2 to produce <u>10.0 moles of NO</u>

2. The neutralization of an acid with a base is a double replacement reaction in which a salt and water are formed. If you start with 25 moles of HCl and neutralize it with  NaOH how many moles of NaCl will be formed?

HCl + NaOH → NaCl + H2O

For 1 mol HCl we need 1 mol NaOH to produce 1 mol of NaCl and 1 mol H2O

For 25 moles of HCl we need 25 moles of NaOH to produce <u>25 moles of NaCl</u> and 25 moles of H2O

3. A car burns gasoline (octane – C8H18) with oxygen. If you drive to Salt Lake and  burn 150 moles of octane how many moles of carbon dioxide are you producing?

2C8H18 + 25O2 → 16CO2 + 18H2O

For 2 moles of octane we need 25 moles of O2 to produce 16 moles of CO2 and 18 moles of H2O

For 150 moles of octane we need 25*75 = 1875 moles of O2

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2Mg + O2 → 2MgO

Moles of Mg = 25.0 g/24.3 g/mol = 1.03 moles

For 2 moles Mg we need 1 mol O2 to produce 2 moles MgO

For 1.03 moles Mg we'll have <u>1.03 moles of MgO</u>

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5. . Lithium reacts with water in a single replacement reaction. How many moles of  hydrogen gas a produced by 10 grams of lithium?

2Li + 2H2O → 2LiOH + H2

Moles Li = 10.0 grams/ 6.94 g/mol = 1.44 moles

For 2 moles Li we need 2 mole H2O to produce 2 moles LiOH and 1 mol H2

For 1.44 moles Li we need 1.44 moles H2O to produce 1.44 moles H2O and <u>0.72 moles H2</u>

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BaCl2 + Na2SO4 → BaSO4 + 2NaCl

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To produce 0.112 moles of AlCl3 and 0.168 moles of Br2

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