Answer:
4.47 x 10²² atoms
Explanation:
Given parameters:
Mass of Bismuth = 15.5g
Unknown:
Number of atoms = ?
Solution:
To find the number atoms, first solve for the number of moles in this element first.
Number of moles = 
Number of moles = 
= 0.074mole
So:
1 mole of a substance contains 6.02 x 10²³ atoms
0.074 mole of Bismuth will contain 0.074 x 6.02 x 10²³ atoms
= 4.47 x 10²² atoms
Answer:
M₂ = 0.9 M
Explanation:
Given data:
Initial Volume = V₁ = 250 mL
Initial molarity = M₁= 3 M
Final volume = 850 mL
Final molarity = ?
Solution:
M₁V₁ = M₂V₂
M₂ = M₁V₁ /V₂
M₂ = 3 M × 250 mL / 850 mL
M₂ = 750 M / 850
M₂ = 0.9 M
KCl : K+ as cation and Cl- as anion
Answer:
0.0983 M
Explanation:
First, we need to find the formulas of the reactants. Potassium forms the ion K⁺, and iodide is the ion I⁻, thus potassium iodide is KI. Silver forms the ion Ag⁺, and nitrate is the ion NO₃⁻, thus silver nitrate is AgNO₃. In the reaction, the cations will be replaced:
KI(aq) + AgNO₃(aq) → KNO₃(aq) + AgI(s)
AgI is an insoluble salt, so it will precipitate, and all nitrates are soluble, thus KNO₃ will be in the ionic form: K⁺ and NO₃⁻. 1 mol of KNO₃ = 1 mol of K⁺.
The molar mass of KI is 166 g/mol, thus the number of moles that is added is:
nKI = mass/molar mass
nKI = 5.71/166 = 0.0344 mol
And the number of moles of AgNO₃ is given as 64mM = 0.064 mol. Because the stoichiometry is 1:1, AgNO₃ is in excess, thus, all the KI will react and form 0.0344 mol of KNO₃. So, nK⁺ = 0.0344 mol. The molarity is the number of moles divided by the volume (350 mL = 0.350 L):
0.0344/0.350 = 0.0983 M
Answer:
Next, the lb will be canceled at 2.2 lb and the kg would be canceled at 1 kg. You cross, multiply, then. 46 x 1 x 1000 is 46000, only moving to the decimal point. 1 x 2.2 x 1 will stay the same, so you'd have 46000 over 2.2.
Explanation:
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