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Mrac [35]
3 years ago
15

Uppose the reaction between naphthalene and 2-bromo-2-methylpropane did not run to completion, so that the limiting reagents wer

e not consumed. how would the two TLC plates have looked in your first and second run in this case?
A)there wouuld have been two spots in both cases

B)There would have been three spots in both cases

C)There would have been four pots in both cases

D)There would have been no distinct spots but only streaks.
Chemistry
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

C)There would have been four pots in both cases

Explanation:

In an incomplete reaction of naphthalene and 2-bromo-2-methylpropane, we started with 2 spots (one each for the two starting materials) and we should end up with 3 spots If spots will appear clearly, one for naphthalene, one for the alkyl halide and one for the product. However, this is possible to have same number of spots initially and finally when we consider 2 spots each for naphthalene and 2-bromo-2-methylpropane then after reaction we have 2 spots of products as each 1 spot of reactants decreases. Finally making initial 4 and final 2+1+1 =4.

So, the answer is (C)

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vladimir2022 [97]

The acid - base equation between H2PO3^- and HS^- is H2PO3^- +  HS^- ⇄S^- + H3PO3.

<h3>What is an acid?</h3>

An acid is a substance that can donate hydrogen ions while a base is a substance that can accept hydrogen ion. This is the acid base definition according to Brownstead - Lowry.

To show the acid - base relationship between H2PO3^- and HS^-, we have the equation;

H2PO3^- +  HS^- ⇄S^- + H3PO3

Learn more about acids and bases: brainly.com/question/10282816

4 0
1 year ago
Where is the mass of an atom found
Virty [35]

Answer:

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5 0
3 years ago
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6 0
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xxMikexx [17]
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