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Mrac [35]
3 years ago
15

Uppose the reaction between naphthalene and 2-bromo-2-methylpropane did not run to completion, so that the limiting reagents wer

e not consumed. how would the two TLC plates have looked in your first and second run in this case?
A)there wouuld have been two spots in both cases

B)There would have been three spots in both cases

C)There would have been four pots in both cases

D)There would have been no distinct spots but only streaks.
Chemistry
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

C)There would have been four pots in both cases

Explanation:

In an incomplete reaction of naphthalene and 2-bromo-2-methylpropane, we started with 2 spots (one each for the two starting materials) and we should end up with 3 spots If spots will appear clearly, one for naphthalene, one for the alkyl halide and one for the product. However, this is possible to have same number of spots initially and finally when we consider 2 spots each for naphthalene and 2-bromo-2-methylpropane then after reaction we have 2 spots of products as each 1 spot of reactants decreases. Finally making initial 4 and final 2+1+1 =4.

So, the answer is (C)

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The standard enthapy of combustion of solid urea co(nh2)2 is -632kjmol-1 at 298k​
Setler79 [48]

Answer:

The standard enthalpy of combustion of solid urea ((CO(NH2)2) is -632 kJ mol-1 at 298 K and its standard molar entropy is 104.60 J K-1 mol-1

Explanation:

8 0
3 years ago
Hemoglobin in your blood does not use elemental iron. It uses iron in the form of Fe2+(aq).
valina [46]

Explanation:

Balanced chemical reaction equation will be as follows.

     2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)

In human body, the neutral iron changes into Fe^{2+}(aq) cation. There will be an oxidation-half reaction and a reduction-half reaction. Equations for this reaction are as follows.

Oxidation: 2Fe^{2+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + 2e^{-}[/tex] .... (1)

Reduction: 2H^{+}(aq) + 2e^{-} \rightleftharpoons H_{2}(g) ...... (2)

On adding both equation (1) and (2), the overall reaction equation will be as follows.

     2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)

Therefore, neutral iron is a part of Heme - b group of Hemoglobin and in an aqueous solution it dissolutes as a part of Heme group. Hence, then it becomes an Fe^{2+} cation.

3 0
3 years ago
When the procedure calls for making a more dilute solution of an acid, or mixing an acid with other solutions, what is the corre
Fed [463]

Answer:

The correct order it b. always add acid last.

Explanation:

Adding acid first could result on a violent reaction and heat or fumes can be generated. The best approach is to always add all the water or non-acid component first, or add a significant portion before adding the acid slowly to the mixture.

7 0
3 years ago
Solve the fo<br> 1. 750 mL =<br> L
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759 mililitera is equal to 0.75 liter
7 0
3 years ago
What is the pressure in millimeters of mercury of 0.0130 molmol of helium gas with a volume of 210. mLmL at 55 ∘C∘C? (Hint: You
juin [17]

Answer : The pressure of the helium gas is, 1269.2 mmHg

Explanation :

To calculate the pressure of the gas we are using ideal gas equation:

PV=nRT

where,

P = Pressure of He gas = ?

V = Volume of He gas = 210. mL = 0.210 L    (1 L = 1000 mL)

n = number of moles He = 0.0130 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of He gas = 55^oC=273+55=328K

Putting values in above equation, we get:

P\times 0.210L=0.0130mole\times (0.0821L.atm/mol.K)\times 328K

P=1.67atm=1269.2mmHg

Conversion used : (1 atm = 760 mmHg)

Thus, the pressure of the helium gas is, 1269.2 mmHg

4 0
3 years ago
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