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-BARSIC- [3]
3 years ago
10

10^3 has what place value?

Mathematics
1 answer:
Pavel [41]3 years ago
5 0

Answer: ten thousand and 3

Step-by-step explanation:

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Find the radius of a circle with circumference of 45.84 meters. Use 3.14
alukav5142 [94]

Answer:

3.8 meters

Step-by-step explanation:

In order to find the circumference for a circle, we use the formula π(radius)²

The circumference give is 45.84 and the π given is 3.14

All we have to do is to just substitute them.

45.84 = 3.14(radius)²

45.84 / 3.14 = radius²

14.6 = radius²

radius = √14.6

radius = 3.82 ≅ 3.8

5 0
3 years ago
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The taxi fare in monopolis city is $1.50 for the first mile and additional mileage charged at the rate of $0.25 for each additio
kifflom [539]

Answer:

5

Step-by-step explanation:

if you add $1.50 +50 cents its $2.00 count by 2's until you get

to 10 and thats 5 how i got 50 cents 25 cents for a half mile

25+25 is 50.

4 0
3 years ago
PLS ANSWER WHAT IS 3 and 14 hundredths minus 1 and 9 hundredths?
k0ka [10]

Answer:

2 and 5 hundredths

Step-by-step explanation:

3 - 1 = 2

14 hundredths - 9 hundredths = 5 hundredths

hence you get 2 and 5 hundredths

6 0
3 years ago
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Shalnov [3]
Have fun but I think it is b and e
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3 years ago
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A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando
Allushta [10]

<u>Answer:</u>

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744  

<u>Solution:</u>

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) \times p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = \frac{\text { number of good coils }}{\text { total number of coils }}

Hence, p(getting 2 good coil for two selection) = \frac{88}{100} \times \frac{88}{100} =\bold{0.7744}

5 0
3 years ago
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