What is the term for a loan with a cosigner?
2 answers:
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Answer:
1)All possible sequences of events V and M by set played that will result in Player V winning the match = VV; MVV; VMV
2) All possible sequences of events V and M by set played that will result in Player M winning the match:
MM; VMM; MVM
3) The probability player V wins the match = 0.4575
4) Probability that a match between Player V and Player M will consist of 3 sets given that Player V wins the match. = 0.3443
The expected number of sets played when Player V competes in a match with Player M = 2.35
Explanation:
Given:
Event player V wins a set = V
Event player M wins a set = M
1)All possible sequences of events V and M by set played that will result in Player V winning the match = VV; MVV; VMV
2) All possible sequences of events V and M by set played that will result in Player M winning the match:
MM; VMM; MVM
3) The probability player V wins the match:
P(V) = P(VV) + P(MVV) + P(VMV)
P(VV) means probability player V wins first and second set. In the first set she had an equal chance of winning, i.e 50%. We are told if she wins first set, probability of winning second set is 0.60.
Therefore, P(VV) = 0.50 * 0.60
= 0.30
P(MVV) means player V lost the first set, but won the remaining two sets.
P(MVV) = 0.50 *(1-0.70) * 0.45
= 0.0675
VMV means player V won the first set, lost the second, and won the third set.
P(VMV) = 0.50 * (1-0.60) * 0.45
= 0.09
Therefore
P(VV) + P(MVV) + P(VMV)
= 0.30 + 0.0675 + 0.09
= 0.4575
Probability V wins is 0.4575
4) Probability that a match between Player V and Player M will consist of 3 sets given that Player V wins the match.
Here it means player V must lose one of the first two sets, but will still win the match.
Calculating, we have:
= 0.344262 ≈ 0.3443
5) The expected number of sets played when Player V competes in a match with Player M.
Let's first find the probability 2 sets are played.
P(2) = P(VV) + P(MM)
We know P(VV) = 0.30
P(MM) = 0.50 * 0.70 = 0.35
Therefore, P(2) = 0.30 + 0.35
P(2)= 0.65
Let's now find probability of 3 sets happening.
P(3) = P(2) not happening
Therefore
P(3) = 1 - P(2)
P(3) = 1 - 0.65 = 0.35
Since probability of 2 sets is 0.65 and probability of 3 sets is 0.35, the expected number of sets will be :
(2 * 0.65) + (3 * 0.35)
= 1.30 + 1.05 = 2.35
The expected number of sets = 2.35
Hello. You forgot to attach the cladogram. The cladogram is attached below.
Answer:
They share a recent common ancestor.
Explanation:
The cladogram is a diagram widely used to show the relationship between the different taxes that make up the species. Using this diagram it is possible to observe the ancestry and biological evolution of living beings over the years.
Each line in the cadogram represents a living being, or a taxon that gave rise to other lines, that is, it gave rise to other living beings. In this case, in the cladogram below we can see that the two organisms highlighted in pink, have lines that originate from the same line, which shows that these organisms share the same ancestor.
