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3 years ago

6

Find the difference. Check your answer by adding. 652,203 - 62,285

1 answer:

Anna11 [10]3 years ago

7 0

The answer is 589,918
Take 652203 and subtract 62,285 from that and you get 589,918

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A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

4 years ago

Mr. Yang has 61 rubber stamps. He wants to give the same number of stamps to each of his 9 students. If he gives away as many st

Eva8 [605]

7 stamps. He will give 6 stamps to them each and there will be 7 left

6 0

3 years ago

0.16% converted into a fraction

kirill115 [55]

1/6 because one divide by six equal 0.166666.....

6 0

4 years ago

Read 2 more answers

Are the graphs of 2x-4y=-12 and y=2x+1 parallel, perpendicular, or neither?

Sauron [17]

Answer:

I believe the answer is neither

Step-by-step explanation:

4 0

2 years ago

Given that vector p=i+2j-2k and q=2i-j+2k, find two vectors m and m satisfying the condition;

Stels [109]

9514 1404 393

Answer:

m = j +k
n = 2i +k

Step-by-step explanation:

There are <em>an infinite number of possibilities</em>. Any vector whose dot-product with p is zero will be perpendicular to p.

Let m = 0i +1j +ak. Then we require ...

m·p = 0 = 0×1 +1×2 +a(-2) ⇒ 0 = 2 -2a ⇒ a = 1

m = 0i +1j +1k

__

Let n = 2i +0j +bk

n·p = 0 = 2×1 +0×2 +b(-2) ⇒ 2 -2b = 0 ⇒ b = 1

n = 2i +0j +1k

6 0

3 years ago