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3 years ago

What is the difference between rutherford's model of the atom and bohr's model of the atom

Physics

1 answer:

Amanda [17]3 years ago

7 0

Answer:

Rutherford described the atom as consisting of a tiny positive mass surrounded by a cloud of negative electrons. Bohr thought that electrons orbited the nucleus in quantised orbits. Bohr built upon Rutherford's model of the atom. ... So it was not possible for electrons to occupy just any energy level.

Explanation:

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I need help with this. -3x-7=18

miskamm [114]

the answer is

-8.33333333

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3 years ago

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A bowler projects an 8-in.-diameter ball weighing 12 lb along an alley with a forward velocity v0 of 15 ft/s and a backspin V0 o

Gala2k [10]

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3 years ago

The Moon requires about 1 month (0.08 year) to orbit Earth. Its distance from us is about 400,000 km (0.0027 AU). Use Kepler’s t

dem82 [27]

Answer:

$\frac{M_e}{M_s} = 3.07 \times 10^{-6}$

Explanation:

As per Kepler's III law we know that time period of revolution of satellite or planet is given by the formula

$T = 2\pi \sqrt{\frac{r^3}{GM}}$

now for the time period of moon around the earth we can say

$T_1 = 2\pi\sqrt{\frac{r_1^3}{GM_e}}$

here we know that

$T_1 = 0.08 year$

$r_1 = 0.0027 AU$

$M_e$ = mass of earth

Now if the same formula is used for revolution of Earth around the sun

$T_2 = 2\pi\sqrt{\frac{r_2^3}{GM_s}}$

here we know that

$r_2 = 1 AU$

$T_2 = 1 year$

$M_s$ = mass of Sun

now we have

$\frac{T_2}{T_1} = \sqrt{\frac{r_2^3 M_e}{r_1^3 M_s}}$

$\frac{1}{0.08} = \sqrt{\frac{1 M_e}{(0.0027)^3M_s}}$

$12.5 = \sqrt{(5.08 \times 10^7)\frac{M_e}{M_s}}$

$\frac{M_e}{M_s} = 3.07 \times 10^{-6}$

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3 years ago

What happens to light as it moves at an angle from a medium that has an

ki77a [65]

Answer:

Explanation:

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3 years ago

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What formula can be used to determine the velocity of an object in free fall?

PtichkaEL [24]

Assuming that you're given either an initial or final velocity, you can use the following equation and solve for the initial or final velocity.

Vyf² = Vyi² - 2g(y - y₀)

Where,
Vyf² = final velocity
Vyi₂² = initial velocity
g = 9.81 m/s²
(y - y₀) = the change in the distance along the y-axis.

You'll need also determine the positive and negative of your y-axis for your final solution because velocity can be positive or negative based on direction. Lastly, don't forget to square root both sides of your equation for your velocity.

I hope this helps.

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3 years ago