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3 years ago

Explain why the types of technology valued can vary.

2 answers:

4 0

Over time, the types of technology can vary and be improved upon so that more advanced techniques become more valued. This could be the situation with mining whereby back in the 1500's in underground mines the rock was broken by fire setting ie lighting a fire below the rock face to heat up the rock and then throwing cold water on it to crack it, so that it could be dug by hand. With the advent of explosives, this all changed so that the rock could be blasted. The increase in advance rates for an underground heading have thus gone from 5-20 feet per month to up to 300meters (984 ft) per month for a 24/7 mining operation, which is a huge improvement.

nirvana33 [79]3 years ago

3 0

ANSWER: Over the years, technology has advanced a lot and has made our lives simpler. We have been seen technological advancements in almost everywhere starting from our workplace to our homes and also at streets.

A classic example of technological advancement can be how people communicate to each other. People previously had only the option of railroads for traveling purposes to distant places. Later, with the introduction of airline industry, people started traveling across countries for many reasons like for business meetings, meeting a relative etc. The entire crowd of business travelers shifted to other technological innovation to save their precious time and money. The technology that replaced the need to travel far across countries was Video Conferencing. A huge number of business travelers opted for this innovation in technology. This advancement also suppressed the cell phone industry which only allowed voice calls at that time.

Also, people used to write mails and used to send telegrams. The telephone came into scenario and gave people an option to communicate faster which previously used to take days to send a message. Then in the 1990's, the email was introduced and gave everyone a platform to send instant and free messages. This gained popularity in 1996-97 with Hotmail services. Later on, it got updated with instant messaging services across the globe like Whatsapp services. Thus, this is how technology varies and are valued accordingly by their usage in that era and the types of technologies grew independently in their respective fields and replaced the outdated ones.

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slavikrds [6]

Answer:

5.38035 m

Explanation:

$n_w$ = Refactive index of water = 1.43

h = Depth = 5.5 m

Critical angle is given by

$\theta_c=sin^{-1}\dfrac{1}{n_w}\\\Rightarrow \theta_c=sin^{-1}\dfrac{1}{1.43}\\\Rightarrow \theta_c=44.37^{\circ}$

d = horizontal distance from the post where she no longer see the bottom of wooden post

So,

$tan\theta_c=\dfrac{d}{h}\\\Rightarrow d=tan\theta_c\times h\\\Rightarrow d=tan44.37\times 5.5\\\Rightarrow d=5.38035\ m$

The distance d is 5.38035 m

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3 years ago

The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation F

UNO [17]

Answer:

The equation which define the work done by spring is w = 45 x³ - 8 x²

Explanation:

Given as :

The force is the function of distance x

I.e F(x) = a x² - b x

where

a = 45 N/m²

b = 8 N/m

Now, Wok done = Force ×displacement

I.e W = F . ds

So , W = (a x² - b x) × x

or, W = (45 x² - 8 x) × x

Or, w = 45 x³ - 8 x²

So, the equation which define the work done by spring is w = 45 x³ - 8 x²

Hence The equation which define the work done by spring is w = 45 x³ - 8 x² Answer

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3 years ago

Determine the 3 standing waves for a 4 m length of rope.

strojnjashka [21]

Harmonics, Loop and Harmonic number

Hope this helps :)

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3 years ago

Which travels at the greatest speed?

lyudmila [28]

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4 years ago

A speed skater is sliding across the ice at a speed of 19 m/s when she encounters a rough patch of ice that is 2.0 m wide. As sh

Stells [14]

Answer:

$-9.25 m/s^2$

Explanation:

The motion of the skater is a uniformly accelerated motion, so we can find the deceleration by using the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

In this problem, we have:

u = 19 m/s is the initial velocity of the skater

v = 18 m/s is the final velocity of the skater

s = 2.0 m is the displacement

Solving for a, we can find the acceleration:

$a=\frac{v^2-u^2}{2s}=\frac{18^2-19^2}{2(2.0)}=-9.25 m/s^2$

And the negative sign tells us that the acceleration is in the opposite direction to the motion (so, it is a deceleration)

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4 years ago