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Dmitry [639]
3 years ago
15

How far does a car travel as it accelerates from 12 m/s to 18 m/s at 3 m/s??

Physics
1 answer:
yulyashka [42]3 years ago
4 0

Answer:

Explanation:

I ASSUME you mean acceleration is 3 m/s²

v² = u² + 2as

s = (v² - u²) / 2a

s = (18² - 12²) / (2(3))

s = 30 m

to verify we can see that the acceleration time is

t = (18 - 12) / 3 = 2 s

s = 0 + 12(2) + ½(3)2² = 30 m

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1.A particle is moving up an inclined plane. Its velocity changes from 15m/s to 10m/s in two seconds. What is its acceleration?
FrozenT [24]

\huge{ \underline{ \boxed{ \bf{ \blue{Solution:}}}}}

<h3><u>Provided</u><u>:</u><u>-</u></h3>
  • Initial velocity = 15 m/s
  • Final velocity = 10 m/s
  • Time taken = 2 s

<h3><u>To FinD:-</u></h3>
  • Accleration of the particle....?

<h3><u>How</u><u> </u><u>to</u><u> </u><u>solve</u><u>?</u></h3>

We will solve the above Question by using equations of motion that are:-

  • v = u + at
  • s = ut + 1/2 at²
  • v² = u² + 2as

Here,

  • v = Final velocity
  • u = Initial velocity
  • a = acceleration
  • t = time taken
  • s = distance travelled

<h3><u>Work</u><u> </u><u>out</u><u>:</u></h3>

By using first equation of motion,

⇛ v = u + at

⇛ 10 = 15 + a(2)

⇛ -5 = 2a

Flipping it,

⇛ 2a = -5

⇛ a = -2.5 m/s² [ANSWER]

❍ Acclearation is negative because final velocity is less than Initial velocity.

<u>━━━━━━━━━━━━━━━━━━━━</u>

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The net force of a heavy, stationary box is?
Leto [7]

Answer:

gravity

Explanation:

7 0
3 years ago
Please help me! I don’t understand how to solve this problem.
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To solve these problems first draw the free body diagram:

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A 10.0-g bullet moving at 300 m/s is fired into a 1.00-kg block at rest. the bullet emerges (the bullet does not get embedded in
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Momentum before the hit:
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Momentum after the hit:
p = 0.01 * 150 + 1 * v

Momentum is conserved:
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v = 1.5

The velocity of the block after the collision is 1.5 m/s.
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