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TEA [102]
3 years ago
14

The cell division process called mitosis is used to make cells called

Biology
2 answers:
denis-greek [22]3 years ago
5 0
Correct Just did it
pantera1 [17]3 years ago
4 0

Answer:

gametes i belive

Explanation:

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The female reproductive system releases eggs through the process of ovulation. the eggs then travel to the uterus, which is the
taurus [48]
I believe the answer is A. True! Good luck with the respond your homework! Anymore questions you can just comment or DM me:)
5 0
3 years ago
Read 2 more answers
I'LL GIVE BRAINLIEST:
ch4aika [34]

Answer:

The grasshopper doesn't have to use it circulatory system to carry gases to and from the grasshopper cells because the air that is passed through the trachea system is already close enough to get to the cells.

Explanation:

"In the grasshopper, exchange of oxygen and carbon dioxide occurs in the tracheal system. Hemolymph plays no part in the process. There is not even an oxygen-carrying pigment in insect hemolymph." - www.biology-pages.info

(Here's some extra info as well)

8 0
3 years ago
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An individual heterozygous for eye color, skin color, and number of eyes mates with an individual who is homozygous recessive fo
sukhopar [10]

Answer:

B) 1 black eyes, green skin, two eyes : 1 black eyes, green skin, one eye : 1 black eyes, white skin, two eyes : 1 orange eyes, green skin, two eyes : 1 orange eyes, white skin, two eyes : 1 orange eyes, white skin, one eye

Explanation:

Parentals:                     BbGgCc  x  bbggcc

The punette square diagram of the cross of these two parents is attached.

B = black eyes, b = orange eyes;

G = green skin, g = white skin;

C = two eyes, c = one eye

Progeny with BbGgCc genotype → black eyes, green skin, two eyes = 8

Progeny with BbGgcc genotype → black eyes, green skin, one eye = 8

Progeny with BbggCc genotype → black eyes, white skin, two eyes = 8

Progeny with bbGgCc genotype → orange eyes, green skin, two eyes = 8

Progeny with Bbggcc genotype → black eyes, white skin, one eye = 8

Progeny with bbGgcc genotype → orange eyes, green skin, one eye = 8

Progeny with bbggCc genotype → orange eyes, white skin, two eyes = 8

Progeny with bbggcc genotype → orange eyes, white skin, one eye = 8

So, if we will see them in the form of ratio then each of the genotype will be in the ratio of 1 i.e. black eyes, green skin, two eyes: black eyes, green skin, one eye: black eyes, white skin, two eyes: orange eyes, green skin, two eyes: black eyes, white skin, one eye: orange eyes, green skin, one eye: orange eyes, white skin, two eyes : orange eyes, white skin, one eye = 1:1:1:1:1:1:1:1.

So, in view of above option B is most appropriate.

Note: In a trihybrid cross, a total of 64 progeny types may be produced.

6 0
3 years ago
What is some strengths as a math learner
irina1246 [14]
Some strengths are,

you get faster at answering questions, it’s easier to understand the problems, you have more strategy’s, you understand the ration and percent. you can use graphs and number lines much easier.


i’m doing mental math right now and this is what we were going over,


i hope it helps
5 0
3 years ago
The nitrogen base pictured is adenine. Is this nucleotide considered a purine or a pyrimidine? There is a molecule, a base of wh
Vlad [161]

Answer: Purine

Explanation:

A purine is a nitrogenous base found in nucleic acids, and contains a 6-membered pyrimidine ring fused to the 5-membered imidazole ring. The most common examples of purine bases are adenine and guanine.

Thus, the nitrogen base pictured is adenine, and the nucleotide considered is a purine

5 0
3 years ago
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