Answer:
C, never negative
it can be zero in exactly one occasion
The derivative of height with respect to time is
h'(t) = -32t +v
This will be zero when
0 = -32t +v
t = v/32
The height at this time is
h(v/32) = -16(v/32)² + v(v/32) = (v²)(-1/(2·32) +1/32) = v²/64
Setting this to 400, we get
400 = v²/64
v = √(64·400) = 160
The initial velocity required so that the maximum height is exactly 400 feet is
160 ft/s.
x^2 - 4
------------------------------
x + 7 | x^3 + 7x^2 - 4x - 28
x^3 + 7x^2
------------------
0 - 4x - 28
-4x - 28
-------------
0
Now we know that
x^3 + 7x^2 - 4x - 28 = (x^2 - 4)(x + 7)
x^2 - 4 can be factored since it is the difference of two squares.
x^2 - 4 = (x + 2)(x - 2)
The complete factoring is:
x^3 + 7x^2 - 4x - 28 = (x +2)(x - 2)(x + 7)
The answer is x=9 I’ve just did this problem once you take 4x+5 you’ll get 8
Answer:
4
Step-by-step explanation: