Changr 20 min in to hr
1 answer:
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<u>For the first question we use point-slope form of an equation</u>
y-
=m(x-
)
y=m(x-)+
then we plug in the known values
y=m(x-4)+7
we leave the slope as variable m since it is undefined
<u>For Question 2
</u>
A line that is parallel to the x-axis is a horizontal line and since the slope of a line is defined as the Δy/Δx (change in y/change in x) and the change in y is 0 at any 2 points observed on the line the slope is 0. (0/any number is 0)
<u>For Question 3
</u>
Following the same relationship as question 2 we can solve for the slope.
Δy/Δx
-
/-
now we plug in the known values from the two points given
(5-7)/(-3-1)
-2/-4
m=1/2 or 0.5
<u><em>and For the Final Question</em></u>
a translation left or right is done by affecting the x variable if you add 2 to x then the x value will have to be 2 less to get the same result...in other words when x is 1 the value of y is also 1...but if I wanted the whole equation translated left 2 unites then I would want the same y-value at an x-value 2 smaller... in other words, in our example x will be -1 when y is 1. For this value found on the graph to match the equation our x value must have 2 added to it in the equation....therefore the equation that translates y=|x| two units left is...
y=|x+2|
y-
y=m(x-
then we plug in the known values
y=m(x-4)+7
we leave the slope as variable m since it is undefined
<u>For Question 2
</u>
A line that is parallel to the x-axis is a horizontal line and since the slope of a line is defined as the Δy/Δx (change in y/change in x) and the change in y is 0 at any 2 points observed on the line the slope is 0. (0/any number is 0)
<u>For Question 3
</u>
Following the same relationship as question 2 we can solve for the slope.
Δy/Δx
now we plug in the known values from the two points given
(5-7)/(-3-1)
-2/-4
m=1/2 or 0.5
<u><em>and For the Final Question</em></u>
a translation left or right is done by affecting the x variable if you add 2 to x then the x value will have to be 2 less to get the same result...in other words when x is 1 the value of y is also 1...but if I wanted the whole equation translated left 2 unites then I would want the same y-value at an x-value 2 smaller... in other words, in our example x will be -1 when y is 1. For this value found on the graph to match the equation our x value must have 2 added to it in the equation....therefore the equation that translates y=|x| two units left is...
y=|x+2|
Answer:
28 N
Explanation:
According to Newton's second law of motion
The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
in another form,
Force = mass * acceleration
assuming mass is a constant since considering the same object , we can say
Force ∝ acceleration