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lutik1710 [3]
2 years ago
5

Changr 20 min in to hr​

Physics
1 answer:
Rom4ik [11]2 years ago
5 0

Answer:

change 20 min into hr = <u>0.33 hr</u>

Explanation:

convert= divide the time by 60 because 60 mins make 1 hr

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What is the resistance force when you walk up an inclined plane?
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Answer:

the resistance force is mg cos(-)

Explanation:

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Light is an example of something that travels in waves. Light waves come in many different varieties, and can be seen as many di
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Answer:

Option (B)

Explanation:

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Thus, the correct answer is option (B).

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3 years ago
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This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The mag
sweet-ann [11.9K]

Answer:

Explanation:

Given

coefficient of kinetic friction(\mu _k)=0.34

inclination \theta =44

weight of block=51 N

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thus

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as block is moving with constant velocity thus F_{net} is zero

f_r=\mu _kN=0.34\times Fcos\theta

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F=\frac{51}{0.45}=113.31 N

(b)When Block slides down the wall friction changes its direction to oppose the block

Fsin\theta -W+f_r=0

F\left ( \sin \theta +\mu \cos \theta \right )=W

F=\frac{W}{\left ( \sin \theta +\mu \cos \theta \right )}

F=\frac{51}{0.939}=54.299 N

3 0
3 years ago
Suppose a star the size of our Sun, but of mass 9.0 times as great, were rotating at a speed of 1.0 revolution every 17 days. If
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Use the conservation of angular momentum; angular momentum at the beginning = angular momentum at the end 
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= 4*(1)*(7E5/7.5)^2
= 3.48E10 revs/(17days)
= 2.04705882 x 10^9 revs/sec
4 0
3 years ago
A 2.0-kg cart collides with a 1.0-kg cart that is initially at rest on a low-friction track. After the collision, the 1.0-kg car
nikitadnepr [17]

To solve this problem we will apply the concepts related to the conservation of momentum. The momentum can be defined as the product between the mass of the object and its velocity, and the conservation of the momentum as the equality between the change of the initial momentum versus the final momentum. Mathematically, this relationship can be described as

m_1u_1+m_2u_2 = m_1v_2+m_2v_2

Here,

m_{1,2} = Mass of each object

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According to the statement one of the bodies does not have initial velocity, therefore said term would be zero. And the equation could be rewritten as,

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Replacing the values respectively (The mass of your body with its respective speed we would have)

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u_1 = \frac{2kg(0.3m/s)+1kg(0.5m/s)}{2kg}

u_1 = 0.55m/s

Therefore the initial velocity of the 2kg cart is 0.55m/s

4 0
2 years ago
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