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3 years ago

Calculate the potential energy stored in an object of mass 50 kg at a height of 20 m from the ground.

Physics

2 answers:

bearhunter [10]3 years ago

8 0

Answer:

potential energy=mgh

=50×10×20

=10000 J

NARA [144]3 years ago

3 0

Answer:

$\huge\boxed{\sf P.E. = 10 kJ}$

Explanation:

Given Data:

Mass = m = 50 kg

Height = h = 20 m

Acceleration due to gravity = g = 10 m/s²

Required:

Potential Energy = P.E. = ?

Formula:

P.E. = mgh

Solution:

P.E. = (50)(20)(10)

P.E. = 10,000 Joules

P.E. = 10 * 10³ Joules (10³ = Kilo)

P.E. = 10 kJ

$\rule[225]{225}{2}$

Hope this helped!

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You're driving down the highway late one night at 20 m/s when a deer steps onto the road 41m in front of you. Your reaction time

nordsb [41]

Answer:

Maximum speed you could have and still not hit the deer = 24.07 m/s

Explanation:

Let the maximum speed you could have and still not hit the deer be y.

Your reaction time before stepping on the brakes is 0.50s.

Distance traveled during this time = 0.5y

A deer steps onto the road 41m in front of you

Remaining distance to deer = 41 - 0.5y

The maximum deceleration of your car is 10 m/s²

We have equation of motion, v² = u² + 2as

Initial velocity, u = y m/s

Final velocity, v = 0 m/s

Acceleration, a = -10 m/s²

Displacement, s = 41 - 0.5y

Substituting,

v² = u² + 2as

0² = y² + 2 x -10 x (41 - 0.5y)

20(41 - 0.5y) = y²

820 - 10 y = y²

y² + 10 y -820 = 0

y = 24.07 m/s or y = -34.06 m/s(not possible)

Maximum speed you could have and still not hit the deer = 24.07 m/s

7 0

4 years ago

The rate (in mg carbon/m3/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function P = 9

Ivanshal [37]

Answer:

At light intensity I = 3, is P a maximum

Explanation:

Given:

$P=\frac{90I}{I^2+I+9}$

now differentiating the above equation with respect to Intensity 'I' we get

$\frac{dp}{dI}=\frac{(I^2+I+9).\frac{d(90I)}{dI}-90I.\frac{d((I^2+I+9)}{dI}}{(I^2+I+9)^2}$

$\frac{dp}{dI}=\frac{(I^2+I+9).90-90I.(2I+1)}{(I^2+I+9)^2}$

$\frac{dp}{dI}=\frac{90I^2+90I+810)-(180I^2+90I)}{(I^2+I+9)^2}$

$\frac{dp}{dI}=\frac{-90I^2+810)}{(I^2+I+9)^2}$

Now for the maxima $\frac{dP}{dI}=0$

thus,

$0=\frac{-90I^2+810)}{(I^2+I+9)^2}$

$-90I^2+810=0$

$I^2=\frac{810}{90}$

$I^2=9$

I = 3

thus, for the value of intensity I = 3, the P is maximum

at I = 3

$P=\frac{90\times3}{3^2+3+9}$

$P=\frac{270}{21}$

$P=12.85$

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4 years ago

True or False: Heavy elements such as Carbon and Nitrogen, that are necessary for life were created in the Big

Orlov [11]

Answer:

i believe the answer is true

Explanation:

everything was created in the big bang

8 0

3 years ago

A transformer connected to a 120-v(rms) at line is to supply 13,000V(rms) for a neon sign.

lyudmila [28]

Answer:

(a) 108

(b) 110.500 kW

Solution:

As per the question:

Voltage at primary, $V_{p} = 120\ V$ (rms voltage)

Voltage at secondary, $V_{s} = 13000\ V$ (rms voltage)

Current in the secondary, $I_{s} = 8.50\ mA$

Now,

(a) The ratio of secondary to primary turns is given by the relation:

$\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{s}}$

where

$N_{p}$ = No. of turns in primary

$N_{s}$ = No. of turns in secondary

$\frac{N_{s}}{N_{p}} = \frac{13000}{120}$ ≈ 108

(b) The power supplied to the line is given by:

Power, P = $V_{s}I_{s} = 13000\times 8.50 = 110.500\ kW$

$\frac{V_{s}}{V_{p}} = \frac{I_{p}}{I_{s}}$

$\frac{13000}{120} = \frac{I_{p}}{8.50}$

$I_{p} = \frac{13000}{120}\times 8.50 = 920.84\ A$

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3 years ago

When a concrete road is heated by energy from the Sun, the Concrete will most likely

yarga [219]

It will most likely expand when hot and contract when cold.

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3 years ago

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