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dexar [7]
3 years ago
7

within ____minutes after a drink is consumed all of the alcoholic content has probably been absorbed into your body

Physics
1 answer:
OverLord2011 [107]3 years ago
3 0

20-60minutes

Explanation:

Within 10-20minutes after a drink is consumed all of the alcoholic content has probably been absorbed into body.

Alcohol is absorbed into the body much more fast.

  • It does not undergo digestion process like food.
  • It can easily be absorbed into the blood stream.
  • Alcohol is readily absorbed and carried round into the body.
  • It doesn't get processed like food in the body where they pass through the digestive system.
  • The body sees alcohol as nutrient.
  • It carries it to the brain and other parts of the body.

learn more;

Alcohol brainly.com/question/4541397

#learnwithBrainly

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At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.5 m/s2. At the same insta
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Answer:

6.96 s

Explanation:

<u>Given:</u>

  • u = initial speed of the automobile = 0 m/s
  • a = constant acceleration of the automobile = 2.5\ m/s^2
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<u>Assume:</u>

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At the moment the automobile and the truck both meat each other the distance travel by both vehicles must be the same.

\therefore \textrm{Distance traveled by the automobile }=\textrm{Distance traveled by the truck}\\\Rightarrow ut+\dfrac{1}{2}at^2=vt\\\Rightarrow (0)t+\dfrac{1}{2}\times 2.5\times t^2=8.7t\\\Rightarrow 1.25t^2=8.7t\\\Rightarrow 1.25t^2-8.7t=0\\\Rightarrow t(1.25t-8.7)=0\\\Rightarrow t = 0\,\,\,or\,\,\, t = \dfrac{8.7}{1.25}\\\Rightarrow t = 0\,\,\,or\,\,\, t = 6.96\\

Since t = 0 s is the initial condition. So, they both meet again at t = 6.96 s such that the automobile overtakes the truck.

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an object at rest starts accelerating if it travels 30 meters to end up going 10 m/s what was it’s acceleration
vfiekz [6]

First we have to calculate the time taken to travel the distance 30 m, is

t = \frac{distance}{velocity} = \frac{30 \ m}{10 \ m/s } =  3 \ s.

Now from equation of motion,

v = u + at

Given, v = 10 \ m/s .

As object starts from rest, so  u = 0.

Substituting these values in above equation, we get

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Thus, the acceleration is 3.33 \ m/s^2

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