The correct answer is true
        
                    
             
        
        
        
Answer:
70 revolutions
Explanation:
We can start by the time it takes for the driver to come from 22.8m/s to full rest:

The tire angular velocity before stopping is:

Also its angular decceleration:

Using the following equation motion we can findout the angle it makes during the deceleration:

where  = 0 m/s is the final angular velocity of the car when it stops,
 = 0 m/s is the final angular velocity of the car when it stops,  = 114rad/s is the initial angular velocity of the car
 = 114rad/s is the initial angular velocity of the car  = 14.75 rad/s2 is the deceleration of the can, and
 = 14.75 rad/s2 is the deceleration of the can, and  is the angular distance traveled, which we care looking for:
 is the angular distance traveled, which we care looking for:

 or 440/2π = 70 revelutions
 or 440/2π = 70 revelutions
 
        
             
        
        
        
It will be 49 Newtons of force in the down direction. To find the force in newtons, you multiply the mass (5 kg) by the gravity (which if 9.8).