Why doesn't the skateboarder rolls as high up the ramp each time you go down the ramp
1 answer:
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Answer: sq. root of .735
Explanation:
multiply two on both sides.
(2) *2,94 = (0,200 * v^2) (2)
588 = 0400 * 2v^2
divide by 400 on both sides
1.47 = 2v^2
divide by 2 on both sides
.735 = v^2
take square root of both sides
or .85732141
Answer:
F = 20.4 i ^
Explanation:
This exercise can be solved using the ratio of momentum and amount of movement.
I = F t = Dp
Since force and amount of movement are vector quantities, each axis must be worked separately.
X axis
Let's look for speed
cos 45 = vₓ / v
vₓ = v cos 45
vₓ = 8 cos 45
vₓ = 5,657 m / s
We write the moment
Before the crash p₀ = m vₓ
After the shock = -m vₓ
The variation of the moment Δp = mvₓ - (-mvₓ) = 2 m vₓ
The impulse on the x axis Fₓ t = Δp
Fₓ = 2 m vₓ / t
Fx = 2 0.450 5.657 / 0.250
Fx = 20.4 N
We perform the same calculation on the y axis
sin 45 = vy / v
vy = v sin 45
vy = 8 sin 45
vy = 5,657 m / s
We calculate the initial momentum po = m
Final moment = m
Variations moment Δp = m - m
= 0
Force in the Y-axis = 0
Therefore the total force is
F = fx i ^ + Fyj ^
F = Fx i ^
F = 20.4 i ^