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Alika [10]
3 years ago
9

Induced EMF and Current in a Shrinking LoopShrinking Loop. A circular loop of flexible iron wire has an initial circumference of

161cm , but its circumference is decreasing at a constant rate of 13.0cm/s due to a tangential pull on the wire. The loop is in a constant uniform magnetic field of magnitude 1.00T , which is oriented perpendicular to the plane of the loop. Assume that you are facing the loop and that the magnetic field points into the loop.Find the magnitude of the emf EMF induced in the loop after exactly time 8.00s has passed since the circumference of the loop started to decrease.
Physics
1 answer:
vodomira [7]3 years ago
4 0

Answer:

Explanation:

Let c be the circumference and r be the radius

c = 2πr , r = c / 2π , area A = π r² = π (c/2π )²  = (1/4π) x c²

flux (ψ) = BA = 1 X 1/4π X c²

dψ/dt = 1/4π x 2c dc/dt =1/2π x c x dc/dt

at t = 8 s

c = 161 - 13 x 8 = 57 cm , dc/dt = 13 cm/s  

e = dψ/dt = (1 / 2π )x 57 x 13 x 10⁻⁴ = 118 x 10⁻⁴ V.

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Answer:

3.9 m/s

Explanation:

We are given that

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Average friction force,f=4.0\times 10^3 N

We have to find the speed of the car at the bottom of the driveway.

Net force,F_{net}=mgsin\theta-f=2.1\times 10^3\times 9.8sin19-4.0\times 10^3

Where g=9.8 m/s^2

Acceleration,a=\frac{F_{net}}{m}=\frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}

v=\sqrt{2as}

v=\sqrt{2\times \frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}\times 5.9}

v=3.9 m/s

7 0
3 years ago
What do miles, kilometers, and light-years have in common?<br><br>​
Radda [10]

They are all units of measure of length

Explanation:

Length is a scalar quantity representing a distance between two points, and it can be expressed in different units.

The SI units of the length is the metre (m), which is defined as the length of the path travelled by light in vacuum during a time interval of 1/299,792,458 of a second.

A unit which is common used is a multiple of the meter, the kilometre (km) which corresponds to 1000 metres:

1 km = 1000 m

Another unit used in the UK system is the mile (mi), where the conversion factor between miles and metres is

1 mi = 1609.34 m

Finally, these units are not suitable to be used to measure astronomical distances - such as those between stars and galaxies. For this, another unit is used, which is the light-year (ly), which corresponds to the distance travelled by the light in a vacuum in one year, and its conversion factor to the metre is:

1 ly = 9.46\cdot 10^{15}ly

Learn more about distance here:

brainly.com/question/3969582

#LearnwithBrainly

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6 0
3 years ago
A rocket explodes into two fragments, one 25 times heavier than the other. The magnitude of the momentum change of the lighter f
V125BC [204]

Answer:

B) The same as the momentum change of the heavier fragment.

Explanation:

Since the initial momentum of the system is zero, we have

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0 = p + p'

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Since the initial momentum of each fragment is zero, the momentum change of lighter fragment Δp = final momentum - initial momentum = p - 0  = p

The momentum change of heavier fragment Δp' = final momentum - initial momentum = p' - 0 = p' - 0 = p'

Since p = -p' and Δp = p and Δp' = -p = p ⇒ Δp = Δp'

<u>So, the magnitude of the momentum change of the lighter fragment is the same as that of the heavier fragment.  </u>

So, option B is the answer

4 0
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<em />

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7 0
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