Answer:
It will take 6 hours for the new pump to drain the pool.
Step-by-step explanation:
As the complete question is not given, the complete question is found online and is attached herewith
Let the rate of new pump is given as x=W/t_1
Let the rate of the old pump is given as y=W/t_2
it is given that the time t_2=2t_1
So by substituting the values of t_2 in the rate equation of y
y=W/2t_1
y=(W/t_1*2)=x/2
Also the total rate of both the pumps is given as W/t3 where t3 is given as 4 hours so the equation becomes
x+y=W/4
x+x/2=W/4
3x/2=W/4
As x=W/t_1
3W/2t_1=W/4
Now as W is same on both sides so
3/2t_1=1/4
12=2t_1
t_1=6 hours
So it will take 6 hours for the new pump to drain the pool.
Answer:
(2,4)
Step-by-step explanation:
The solution for the system is where the two lines intersect.
The two lines intersect at x = 2 and y =4
(2,4)
The domain would negative infinity to positive infinity . Domain would be the smallest through the largest possibly value of X. If you also need the range it’s ( -4,infinity]
<span>4(6) + 7 (5 - 3 )
= 24 + 7(2)
= 24 + 14
= 38
answer
</span><span>D: 38</span>
Answer:
bka bla bla bla sorry I newbie