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3 years ago

- 4y³ – 7y²– 2y ² – 7x – 4y² + y²

Mathematics

2 answers:

kupik [55]3 years ago

8 0

Answer:-4y^3-12y^2-7x

Step-by-step explanation:

nikklg [1K]3 years ago

7 0

Answer:-4y^3-12y^2-7x

Step-by-step explanation:if you collect the liked terms it will add up to get that

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PLEASE HURRY In order to solve the system of equations below, Juana multiplies each equation by a constant to eliminate the y te

Doss [256]

Answer:

16x -12y = 4

15x +12y = 27

Step-by-step explanation:

4x-3y = 1

5x+4y=9

Multiply the first equation by 4

16x -12y = 4

Multiply the second equation by 3

15x +12y = 27

7 0

4 years ago

Read 2 more answers

Write the equation of the line that passes through (-1, -3) and is parallel to the line that passes through (10, 3) and (7, -1).

REY [17]

Answer:

y=4/3 x -5/3

Step-by-step explanation:

Please see attached picture for full solution.

8 0

3 years ago

PLEASE HELP ME FAST!!!!

adoni [48]

Answer:

A is the only possible correct answer since the center of that shape is x =-1

6 0

3 years ago

In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

$x^{3} +64$ = 0

We can write 64 as $4^{3}$

$x^{3}$ + $4^{3}$ = 0

using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

= $(x+4) (x^{2} -x*4+4^{2} )$

= $(x+4)(x^{2} -4x+16)$ ....................(1)

solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

$x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}$

$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

$x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

3 0

3 years ago

What is the m∠ACB in the circle shown below?

GuDViN [60]

Question:

What is the m∠ACB in the circle shown below?

Answer:

Step-by-step explanation:

So we know it is less than a right angle and it is not a obtuse angle it is less than 90 degrees. 45 is less, 90 is equal(not what we are looking for) , 120, is greater, and 180 is greater which leaves us to our answer 45.

4 0

3 years ago

- 4y³ – 7y²– 2y ² – 7x – 4y² + y²​

- 4y³ – 7y²– 2y ² – 7x – 4y² + y²