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Serggg [28]
3 years ago
12

What is often found around the perimeter of a yard

Mathematics
1 answer:
sp2606 [1]3 years ago
5 0
A fence I think

I hope this was the answer you were looking for

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Instruction: use the ratio of a 30-60-90 triangle to solve for the variables. Leave your answers as radicals in simplest form.u=
almond37 [142]

Let's start by identify a 30-60-90 triangle

If we compare those two traingles we can stablish the following relation:

\begin{gathered} a\sqrt[]{3}=6\sqrt[]{3} \\  \end{gathered}

Therefore, a=6

u is the opposite side to the 90° angle, therefore

\begin{gathered} u=2a \\ u=2\cdot6 \\ u=12 \end{gathered}

on the other hand, v is the opposite side to the 30° angles, so

\begin{gathered} v=a \\ v=6 \end{gathered}

6 0
1 year ago
Help me solve this please, im really bad at stuff like this
omeli [17]

Answer:

given

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Given:SW is diameter of circleR<br><br> m\overarc ST = 30\degree<br><br> Prove: RTW = 15\degree
Ostrovityanka [42]

Check the picture below.

we know that the arcST is 30°, meaning the inscribed angle intercepting it will be half that or 15°.

in the triangle RWT, two sides of it are RT and RW, both of which are radius segments and thus equal, meaning that triangle RWT is an isosceles, and in an isosceles the twin sides also make twin angles, meaning that ∡RTW is a twin of the inscribed angle ∡RWT.

4 0
2 years ago
I need this fast guys. This is due tomorrow help a fellow comrade out
gavmur [86]
So whats the answer. please help me I got a test of this
3 0
3 years ago
Can someone help me with this question?
arlik [135]

Try this solution:

1. m∠A=m∠L; m∠B=m∠M and m∠C=m∠N;

2. m∠B=m∠M=35° and m∠C=m∠N=95°;

3. m∠A=m∠L=180°-(m∠B+m∠C)=180-35-95=50°

answer: 50°

5 0
3 years ago
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