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3 years ago

How much work will a machine with a power rating of 1.1 x 10^3 watts do in 2.0 hours?

Physics

2 answers:

eduard3 years ago

8 0

The answer to this question is 7.92 * 10^6 J

Hatshy [7]3 years ago

4 0

Power Rating = $1.1 \times 10^3$ W

Time for which the machine is operating = 2 hours

Time in seconds = 2 × 60 × 60

Time = 7200 seconds

Now, we need to use the formula for work done.

Work done = Power × time

Work done = $1.1 \times 10^3 \times 7200$

Work done = $7.92 \times 10^6$ Joules

Hence, work done by the machine in 2 hours is $7.92 \times 10^6$ J.

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The magnitude of the total friction force exerted by the road on the tires at B will be 919.46 lb.

<h3>What is the friction force?</h3>

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. Its unit is Newton (N).

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The normal force is;

$\rm F_n = \frac{3220}{32.2} \times \frac{66^2}{600} \\\\ F_N =726 \ lb$

The net or the total friction force exerted by the road on the tires at B. is found as;

$\rm F = \sqrt{(565)^2+(726)^2} \\\ F = 919.946 \ lb$

Hence, the magnitude of the total friction force exerted by the road on the tires at B will be 919.46 lb.

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