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Setler [38]
4 years ago
12

How much work will a machine with a power rating of 1.1 x 10^3 watts do in 2.0 hours?

Physics
2 answers:
eduard4 years ago
8 0

The answer to this question is 7.92 * 10^6 J

Hatshy [7]4 years ago
4 0

Power Rating = \(1.1 \times 10^3\) W

Time for which the machine is operating = 2 hours

Time in seconds  = 2 × 60 × 60

Time = 7200 seconds

Now, we need to use the formula for work done.

Work done = Power × time

Work done = \( 1.1 \times 10^3 \times 7200\)

Work done = \(7.92 \times 10^6\) Joules

Hence, work done by the machine in 2 hours is \(7.92 \times 10^6\) J.

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The pulley has an efficiency of 78%. How much useful work does the pulley do if you perform 775 J of work on the pulley
LekaFEV [45]

Answer:

605 J

Explanation:

Efficiency = work out / work in

0.78 = W / 775 J

W = 605 J

4 0
3 years ago
Which statement correctly compares the speed of light
Elodia [21]

The speed of light in glass is slower than the speed of light through space.


4 0
4 years ago
Read 2 more answers
An object is in simple harmonic motion. Find an equation for the motion given that the frequency is 3⁄π and at time t = 0, y = 0
Delicious77 [7]

Answer: y(t)= 1/π^2 sin(6*π^2*t)

Explanation: In order to solve this problem we have to consider the general expression for a harmonic movement given by:

y(t)= A*sin (ω*t +φo) where ω is the angular frequency. A is the amplitude.

The data are: ν= 3π; y(t=0)=0 and y'(0)=6.

Firstly we know that 2πν=ω then ω=6*π^2

Then, we have y(0)=0=A*sin (6*π^2*0+φo)= A sin (φo)=0 then φo=0

Besides y'(t)=6*π^2*A*cos (6*π^2*t)

y'(0)=6=6*π^2*A*cos (6*π^2*0)

6=6*π^2*A then A= 1/π^2

Finally the equation is:

y(t)= 1/π^2 sin(6*π^2*t)

3 0
3 years ago
Read 2 more answers
Which has more momentum, a 2.0 kg dog at 41 m/s or a 75 kg pony at 1.0 m/s?
Nesterboy [21]

Answer:

The dog has more momentum than the pony.

Explanation:

To solve this problem, we must remember the formula for calculating momentum, which is given below:

momentum = p = m*v

where m represents the mass of the object and v represents the velocity of the object

Using this knowledge, let's calculate the momentum for the dog and the pony.

Dog: p = m*v = (2kg)*(41 m/s) = 82 kg*m/s

Pony: p = m*v = (75kg)*(1 m/s) = 75 kg*m/s

Since 82 > 75, we can conclude that the dog has more momentum.

Hope this helps!

3 0
4 years ago
Suppose that a comet has a very eccentric orbit that brings it quite close to the Sun at closest approach (perihelion) and beyon
Nutka1998 [239]

Answer:

16.63min

Explanation:

The question is about the period of the comet in its orbit.

To find the period you can use one of the Kepler's law:

T^2=\frac{4\pi}{GM}r^3

T: period

G: Cavendish constant = 6.67*10^-11 Nm^2 kg^2

r: average distance = 1UA = 1.5*10^11m

M: mass of the sun = 1.99*10^30 kg

By replacing you obtain:

T=\sqrt{\frac{4\pi}{GM}r^3}=\sqrt{\frac{4\pi^2}{(6.67*10^{-11}Nm^2/kg^2)(1.99*10^{30}kg)}(1.496*10^8m)^3}\\\\T=997.9s\approx16.63min

the comet takes around 16.63min

8 0
3 years ago
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