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vivado [14]
3 years ago
5

When the net force of opposite forces is zero, the forces are

Physics
2 answers:
Bumek [7]3 years ago
8 0
The answer is D, balanced.

Sloan [31]3 years ago
7 0

Answer:

the answer is balanced

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Your code returns a number of 99.123456789 +0.00455679 for your calculation. How should you report it in your lab write-up?
Aneli [31]

Answer: Your code returns a number of 99.123456789 +0.00455679

Ok, you must see where the error starts to affect your number.

In this case, is in the third decimal.

So you will write 99.123 +- 0.004 da da da.

But you must round your results. In the number you can see that after the 3 comes a 4, so the 3 stays as it is.

in the error, after the 4 comes a 5, so it rounds up.

So the final presentation will be 99.123 +- 0.005

you are discarding all the other decimals because the error "domains" them.

6 0
3 years ago
True Or False;
tino4ka555 [31]
False: because atoms are base on the elements on the periodic table.
3 0
3 years ago
A uniform solid cylinder with a radius of 10 cm and a mass of 3.0 kg is rotating about its center with an angular speed of 33.4
DENIUS [597]

Answer:

Is the equation for Ec=1/2 m(Dv)^2 where Dv is the difference between the angular speed & the areolar speed?

5 0
3 years ago
for an ideal monoatomic gas, the internal energy U os due to the kinetic energy and U=3/2RT per mole.show that cv=3/2R per mole
sladkih [1.3K]

Answer:

i. Cv =3R/2

ii. Cp = 5R/2

Explanation:

i. Cv = Molar heat capacity at constant volume

Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT

Differentiating U with respect to T, we have

= d(3/2RT)/dT

= 3R/2

ii. Cp - Molar heat capacity at constant pressure

Cp = Cv + R

substituting Cv into the equation, we have

Cp = 3R/2 + R

taking L.C.M

Cp = (3R + 2R)/2

Cp = 5R/2

3 0
3 years ago
A woman in a sprint race accelerates from rest to 8.7 m/s in 2.7 s. What is her displacement?​
Trava [24]

Answer:

23.49m

Explanation:

Distance =  velocity x time

8.7 x 2.7 = 23.49m

8 0
2 years ago
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