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Lina20 [59]
3 years ago
8

Find the slope and the y-intercept of the of the linear equation. 0=2-3y+12x

Mathematics
1 answer:
andrew11 [14]3 years ago
4 0

The slope is 4 and the y-intercept is \frac{2}{3}

Step-by-step explanation:

The general form of a linear equation is Ax + By + C = 0, where

  • A is the coefficient of x
  • B is the coefficient of y
  • C is the numerical term
  • A, B, and C are integers
  • The slope of the line = \frac{-A}{B}
  • The y-intercept = \frac{-C}{B}

∵ The linear equation is 0 = 2 - 3y + 12x

- Switch the two sides and arrange the terms as the general

   form above

∴ 12x - 3y + 3 = 0

∴ A = 12

∴ B = -3

∴ C = 2

∵ The slope of the line = \frac{-A}{B}

- Substitute A by 12 and B by -3

∴ The slope of the line = \frac{-12}{-3}

∴ The slope of the line = 4

∵ The y-intercept = \frac{-C}{B}

- Substitute C by 2 and B by -3

∴ The y-intercept = \frac{-2}{-3}

∴ The y-intercept = \frac{2}{3}

The slope is 4 and the y-intercept is \frac{2}{3}

Learn more:

You can learn more about the linear equation in brainly.com/question/4819659

#LearnwithBrainly

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Answer:

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Step-by-step explanation:

BD is only half of BF so find the answer for BF and then divide by @ and you have your answer.

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Answer:

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Step-by-step explanation:

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If a polygon is a square, then it is also a rectangle.<br><br><br> True<br><br> or <br><br> False
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Answer:

true

Step-by-step explanation:

a square will always be a rectangle but a rectangle will not always be a square.

7 0
4 years ago
Read 2 more answers
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

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Answer:

I gave you most of the answer. I'll let you check my work and find the point using the solution.

Step-by-step explanation:

The first thing we do is we divide by negative one in the first equation to get

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Plug in y = -x and get

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Plug 6 back in to the second equation.

-3x + 3y = -36

-3(6) + 3y = -36

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3y = -18

y = -6

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