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2 years ago

HALP ME Find the area.

Mathematics

1 answer:

zhenek [66]2 years ago

5 0

You work out the area of each square so the first one is 3x4 = 12 and the second is 2x4=8 so add them together 12+8=20

Answer = 20 units

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PLS QUICK I ONLY HAVE 2 HOURS

UNO [17]

Answer:

Step-by-step explanation:

As you can observe from the pattern, the numerator gets multiplied by 4 every increase in the sequence.

So , clearly, the 5th term will be = $\frac{64*4}{5} =\frac{256}{5}$

and the 6th term will be = $\frac{256*4}{5} =\frac{1024}{5}$

Therefore , D will be the answer.

6 0

1 year ago

Which graph represents exponential decay?

xz_007 [3.2K]

Answer:

(d) -- see attached

Step-by-step explanation:

A graph that shows exponential decay is one that tends toward a horizontal asymptote as x gets large.

A basic (parent) exponential decay curve is concave upward and tends toward zero as x gets large. The fractional change in any interval is the same as for any other interval of equal size. The curve attached decreases by a factor of 2 when x increases by 1.

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2 years ago

Q.3 Write the factors of 28 in circle A and the factors of 32 in circle B. Write

marissa [1.9K]

Answer: The largest common factor of 28 and 32 is 4.

Step-by-step explanation:

The factors of 28 are 1, 2, 4, 7, 14, 28

The factors of 32 are 1, 2, 4, 8, 16, 32

5 0

1 year ago

Point G is located at (6, 2) on the coordinate plane. Point G is reflected over the y -axis to create point G^ prime . What orde

Lilit [14]

Answer:

The ordered pair that best describes the location of G' is (-6,2).

Step-by-step explanation:

Reflecting a point over the y-axis:

When a point (x,y) is reflected over the y-axis, it's x coordinate is multiplied by -1, while the y-coordinate stays the same. Thus:

(x,y) -> (-x,y).

Point G is located at (6, 2)

When reflected over the y-axis:

G'(-6,2).

The ordered pair that best describes the location of G' is (-6,2).

5 0

2 years ago

Determine

mihalych1998 [28]

Answer:

$=4.+2.$

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector $\vec b$ is a linear combination of $\vec a_1$ and $\vec a_2$ if there are two scalars $x_1, x_2$ such as

$\vec b=x_1\vec a_1+x_2\vec a_2$

In our case, all the vectors are given in $R^3$ but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.