<span>In this case, the value of the first 3 (the ten-thousands) has a value of 30,000. The 3 next to it, in the hundred-thousands place, has a value of 300,000. To compare the two, the 3 on the right has a value one-tenth as much as that on the left.</span>
Answer:
Ans: H and A
Step-by-step explanation:
By the identity:
1-(cos(x))
Ans: H
For second quesiton, the transformation of a graph is that:
f(x) + k means vertical translation up by k units
Two curve have the same maximum value, so the graph doesn't translate upwards or downwards, thus b=0
Ans: A
Answer:
A=8x-8
B=5x+25
A=B(BEING corresponding angles)
8x-8=5x+25
8x-5x=25+8
3x=33
x=33/3
x=11
now 8x-8= 8×11-8
= 88-8
=80
5x+25= 5×11+25
=55+25
= 80
A=B#
Answer:
Step-by-step explanation:
a)
428721
Place of 2's 10s and 10,000s
Therefore its value is 20 and 20,000
Product of the place value = 20 x 20,000 = 4,00,000
b)
37,20,861
Place of 7 is 1,00,000
Therefore the place value is 7,00,000
c)
Greatest 7 digit number is 99,99,999
Adding 1 to it = 99,99,999 + 1 = 1,00,00,000
d)
85642 = 80000 + 5000 + 600 + 40 +2
e)
round off 85642 to nearest thousand = 86,000
Answer:
Rachel
Step-by-step explanation:
We need to measure how far (towards the left) are the students from the mean in<em> “standard deviations units”</em>.
That is to say, if t is the time the student ran the mile and s is the standard deviation of the class, we must find an x such that
mean - x*s = t
For Rachel we have
11 - x*3 = 8, so x = 1.
Rachel is <em>1 standard deviation far (to the left) from the mean</em> of her class
For Kenji we have
9 - x*2 = 8.5, so x = 0.25
Kenji is <em>0.25 standard deviations far (to the left) from the mean</em> of his class
For Nedda we have
7 - x*4 = 8, so x = 0.25
Nedda is also 0.25 standard deviations far (to the left) from the mean of his class.
As Rachel is the farthest from the mean of her class in term of standard deviations, Rachel is the fastest runner with respect to her class.
