Question

The density of nuclear matter is about 1018 kg/m3. Given that 1 mL is equal in volume to 1 cm3, what is the density of nuclear matter in megagrams per microliter (that is, Mg/µL)?

Answer 1

Answer:

density is $10^{6}$ Mg/µL

Explanation:

given data

density of nuclear = $10^{18}$ kg/m³

1 ml = 1 cm³

to find out

density of nuclear matter in Mg/µL

solution

we know here

1 Mg = 1000 kg

so

1 m³ is equal to $10^{6}$ cm³

and here 1 cm³ is equal to  1 mL

so we can say 1 mL is equal to 10³ µL

so by these we can convert density

density = $10^{18}$ kg/m³

density = $10^{18}$ kg/m³ × $\frac{10^{-3} }{10^{6} }$  Mg/µL

density =  $10^{6}$ Mg/µL

Answer 2

Answer: density of nuclear matter will be $10^{-12}Mg/\mu L$

Explanation:-

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given:

Density of nuclear matter= $1018kg/m^3$

1 ml = $1cm^3$

1 kg = 0.001 Mg

Thus $1018kg=\frac{0.001}{1}\times 1018=1.018Mg$

Also $1m^3=10^9\mu L$

Putting in the values we get:

$Density=\frac{0.001Mg}{10^9\mu L}=10^{-12}Mg/\mu L$

Thus density of nuclear matter will be $10^{-12}Mg/\mu L$