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crimeas [40]
3 years ago
14

What is the speed of sound in dry air at 0°C? A. 316 meters/second B. 331 meters/second C. 346 meters/second D. 373 meters/secon

d
Physics
2 answers:
Katena32 [7]3 years ago
8 0

Answer:

1,450 meters per second

Explanation:

amm18123 years ago
3 0

Answer:

The speed of sound in dry air at 0°C is 331 meters/second

Explanation:

Sound wave is a longitudinal wave. The speed of sound depends on the density and compressibility of the medium. If the density of the medium is less, then it will have faster speed of sound and if the compressibility of the medium is high, it will have slower speed of sound.

It also depends on the temperature. At 20 degrees Celsius, the speed of sound is 343 m/s. At 25 degrees Celsius, its speed is 346 m/s and at 0 degrees Celsius, the speed of sound in dry air is 331.3 m/s

The formula is as follows :

v=(331.3+0.606\times T)\ m/s

T = 0°C

v = 331.3 m/s

or

v = 331 m/s

So, the correct option is (b) "331 meters/second".

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How many ounces is 200 lbs converted
ddd [48]

Answer:

3,200 ounces

Explanation:

1 pound (lb) is equal to 16 ounces (oz):

i.e 1 lb = 16 oz

Given:

200 pounds

To find:

2,000 pounds as ounces.

Steps:

200 (mass) * 16 = 3,200 ounces.

Thank you!

- EE

3 0
2 years ago
Read 2 more answers
A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long
Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

W=-\mu mg\times l

Put the value into the formula

W=-0.30\times62\times9.8\times3.50

W=-637.98\ J

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}

\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}

Final potential energy is zero

So, \dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl

Put the value into the formula

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50

v_{2}=\sqrt{2\times55.915}

v_{2}=10.57\ m/s

The speed of skier is 10.57 m/s.

Hence,  (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

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3 years ago
What are the first organisims to live within a newly created patch of land
horrorfan [7]
The first organisms to live within a newly created patch of land are the Pioneer Species.
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3 years ago
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A player kicks a football from ground level with an initial velocity of 27.0 30.0 above the horizontal Find the ball's maximum h
stepladder [879]

Answer:

Given

initial velocity (u) =27.030

Force of gravidity g) =9.8

Rtc maximum height Hmix =?

sln \\ \  hmix = u {}^{2}  \div 2g \\ 27.030 \div 2 \times 9 \\  \\ hmix = 38.025m

5 0
2 years ago
Which sentence describes Newton's first law?
Marrrta [24]

\Large{\red{\bf{\blue{\dag} Answer:-}}}

Newton's First Law of Motion :

An object stays in rest or in uniform motion unless and until compelled by an external unbalanced force . This is also known as " Law of Inertia " .

Here this statement is best represented by the statement : <em>Unbalanced forces cause an object to move.</em><em> </em>[ option c ]

<u>More</u><u> to</u><u> know</u><u> </u><u>:</u><u>-</u>

Newton's 3 laws of motion :-

Newton's First Law of Motion :-

It states that an object stays in rest or in uniform motion unless and until compelled by an external unbalanced force . This is also known as " Law of Inertia " .

Ex - (i) We tend to fall backwards while standing in the bus , when it starts suddenly.

(ii) We tend to fall forward while standing in the bus , when it stops suddenly.

Newton's Second Law of Motion :-

It states that the rate of change of momentum is directly proportional to the applied force in the direction of the force . That is ∆p \propto Force .

Ex - (i) When we push car & a truck with same force the car will have Greater acceleration due to less mass . (Imaginary case ).

(ii) We feel easy to push a empty cart than a full cart .

Newton's Third Law of Motion :-

It states that every action has equal and opposite reaction .

Ex - (i) We are able to walk on ground due to Newton's third law of motion .

(ii) When we push wall it also applies equal and opposite force .

8 0
3 years ago
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