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crimeas [40]
3 years ago
14

What is the speed of sound in dry air at 0°C? A. 316 meters/second B. 331 meters/second C. 346 meters/second D. 373 meters/secon

d
Physics
2 answers:
Katena32 [7]3 years ago
8 0

Answer:

1,450 meters per second

Explanation:

amm18123 years ago
3 0

Answer:

The speed of sound in dry air at 0°C is 331 meters/second

Explanation:

Sound wave is a longitudinal wave. The speed of sound depends on the density and compressibility of the medium. If the density of the medium is less, then it will have faster speed of sound and if the compressibility of the medium is high, it will have slower speed of sound.

It also depends on the temperature. At 20 degrees Celsius, the speed of sound is 343 m/s. At 25 degrees Celsius, its speed is 346 m/s and at 0 degrees Celsius, the speed of sound in dry air is 331.3 m/s

The formula is as follows :

v=(331.3+0.606\times T)\ m/s

T = 0°C

v = 331.3 m/s

or

v = 331 m/s

So, the correct option is (b) "331 meters/second".

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3 years ago
A vertical cylindrical tank 10 ft in diameter, has an inflow line of 0.3 ft inside diameter and an outflow line of 0.4 ft inside
neonofarm [45]

Answer:

\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}, level is rising.

Explanation:

Since liquid water is a incompresible fluid, density can be eliminated of the equation of Mass Conservation, which is simplified as follows:

\dot V_{in} - \dot V_{out} = \frac{dV_{tank}}{dt}

\frac{\pi}{4}\cdot D_{in}^2 \cdot v_{in}-\frac{\pi}{4}\cdot D_{out}^2 \cdot v_{out}= \frac{\pi}{4}\cdot D_{tank}^{2} \cdot \frac{dh}{dt} \\D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out} = D_{tank}^{2} \cdot \frac{dh}{dt} \\\frac{dh}{dt}  = \frac{D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out}}{D_{tank}^{2}}

By replacing all known variables:

\frac{dh}{dt} = \frac{(0.3 ft)^{2}\cdot (5 \frac{ft}{s} ) - (0.4 ft)^{2} \cdot (2 \frac{ft}{s} )}{(10 ft)^{2}}\\\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}

The positive sign of the rate of change of the tank level indicates a rising behaviour.

6 0
4 years ago
If X And Y two vectors have same magnitude, if X^Y=2 and X.Y =4 so, the angle between them ?​
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3 years ago
Two stationary positive point charges, charge 1 of magnitude 3.90 nC and charge 2 of magnitude 1.80 nC, are separated by a dista
soldi70 [24.7K]

Answer:

v = 7793150 m/s

Explanation:

First, we are going to calculate the electrical potential in the point middle between the two charges

Remember that the electrical potential can be calculated as:

v = \frac{kQ}{r}

                 Where     k = 8.9874 x 10^{9} \frac{Nm^{2} }{C^{2} }

and it is satisfy the superposition principle, thus

v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.23} +  \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.23}

v = 222.73v

The electrical potential at 10 cm from charge 1 is:

v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.1} +  \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.36}

v = 395.44 v

Since the work - energy theorem, we have:

q\Delta v = \frac{mv^{2} }{2}

                     where q is the electron's charge and m is the electron's mass

Therefore:

v = \sqrt{\frac{2q\Delta v}{m} }

v = 7793150 m/s

6 0
3 years ago
Why can a hurricane cause so much destruction?
vodka [1.7K]

Answer:

When a cyclone continues to be out over the ocean, the winds and huge waves that area unit created by the storm become dangerous for ships and alternative water vessels. ... once the cyclone approaches land it will cause an enormous quantity of injury. Flooding caused by storm surges is one among the foremost dangerous components of a cyclone.

8 0
3 years ago
Read 2 more answers
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