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Zarrin [17]
2 years ago
12

determine the approximate time, compass heading, distance, and fuel consumed during climb cruising altitude 6,500

Physics
1 answer:
Maslowich2 years ago
8 0

The approximate time, compass heading, distance, and fuel consumed during the climb cruising altitude of 6,500 are <u>17 minutes, 224°, 36 NM, and 3.7 gallons.</u>

<h3>What is compass heading?</h3>
  • The compass heading that the bow or nose of the ship is pointing is known as the heading of a vessel or an aircraft in navigation.
  • Keep in mind that the compass heading may not always correspond to the vehicle's actual route or track, which is the direction it actually moves.
  • The motion of the underlying medium, such as the air or water, or other factors like skidding or slipping, is the cause of any discrepancy between the compass heading and course.
  • The wind triangle can be used to calculate the drift, which is the difference. There have been described at least seven different methods of measuring a vehicle's heading.

To learn more about compass heading with the given link

brainly.com/question/12704364

#SPJ4

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3 years ago
A 128 gram Radium-226 sample with a half-life of 2.25 billion years is found. How many grams will remain after two half-lives?
Bess [88]

Answer:

Option B. 32 g

Explanation:

From the question given above, the following data were obtained:

Original amount (N₀) = 128 g

Half-life (t½) = 2.25 billion years

Number of half-lives (n) = 2

Amount remaining (N) =?

The amount of 128 gram of Radium-226 that will remain after 2 half-lives has elapsed can be obtained as followb

N = 1/2ⁿ × N₀

N = 1/2² × 128

N = 1/4 × 128

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3 years ago
How does an airbag help protect a passenger in a car accident?
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8 0
3 years ago
Read 2 more answers
Using this information...
Pepsi [2]

19.2\:\text{m/s}

Explanation:

At the top of the tree, the velocity of the pebble is purely horizontal so we can calculate it as

v_{y} = v_{0y} = v_0\cos 40° = (25\:\text{m/s})(0.766)

\:\:\:\:\:= 19.2\:\text{m/s}

6 0
3 years ago
What is the gravitational force between a 45 kg person, and the Earth at 5.98 x 1024 kg, with a distance of
Assoli18 [71]

Answer:

C. 441 N

Explanation:

Gravitational force between two objects can by calculated by the formula

= G m₁m₂ / r² , m₁ and m₂ are masses at distance r

= ( 6.67 x 10⁻¹¹ x 45 x 5.98 x 10²⁴) / ( 6.38 x 10⁶ )²

= 44.09 x 10

= 440.9 N

= 441 N .  

7 0
3 years ago
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