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1 year ago

determine the approximate time, compass heading, distance, and fuel consumed during climb cruising altitude 6,500

1 answer:

8 0

The approximate time, compass heading, distance, and fuel consumed during the climb cruising altitude of 6,500 are 17 minutes, 224°, 36 NM, and 3.7 gallons.

<h3>What is compass heading?</h3>

The compass heading that the bow or nose of the ship is pointing is known as the heading of a vessel or an aircraft in navigation.
Keep in mind that the compass heading may not always correspond to the vehicle's actual route or track, which is the direction it actually moves.
The motion of the underlying medium, such as the air or water, or other factors like skidding or slipping, is the cause of any discrepancy between the compass heading and course.
The wind triangle can be used to calculate the drift, which is the difference. There have been described at least seven different methods of measuring a vehicle's heading.

To learn more about compass heading with the given link

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The total capacitance of two 15uF capacitors connected in parallel is

Yuri [45]

The total capacitance of two 15uF capacitors connected in parallel is 30 μF .

7 0

3 years ago

From an h = 53 feet observation tower on the coast, a Coast Guard officer sights a boat in difficulty. The angle of depression o

maksim [4K]

Answer:

757,93 feets

Explanation:

We can make a right triangle between the boat (A), the Coast Guard officer (B) and the base of the observation tower (C), like in the graph attached. Now, you could also made a rectangle, adding the horizontal at the height of the Coast Guard, starting in B and ending in D, the vertex opossing C.

The angle of depression, its O in the graph.

Now, as we got an rectangle, of course, the segment AD its the same length as CB, and CA, the distance from the boat to shoreline, its the same length as DB.

ADB its an right triangle, with AB, the hypothenuse, and BD and DA, the catheti (or legs).

Now, we know the lenght BC, the height of the tower, 53 feets, so we also know the lenght of DA. DA its the opposite cathetus to the angle O. We wish to know the length AC, equal to the lenght DB, the adjacent cathetus of the angle O.

Know, the trigonometric function that connects the adjacent cathetus with the opossite cathetus its the tangent.

$tangent( O ) = \frac{opposite}{adjacent}$

We can take that the angle O = 4 °, and knowing that the opossite cathetus its 53 feets, we got:

$tangent( 4) = \frac{53 feets}{DB}$

$DB= \frac{53 feets}{tangent( 4)}$

$DB= 757,93 feets$

This its equal to the distance from the boat to the shoreline.

4 0

3 years ago

Ivan exerts 20 N of force to lift a basket 2 m. He then carries the basket 5 m across a room to place it on a shelf. Ivan does w

amid [387]

A) Ivan does work when he lifts the basket

B) Work = Force * displacement
W = 20 * 2
W = 40 Joules

So, The Amount of work he does is 40 Joules

Hope this helps!

7 0

2 years ago

Read 2 more answers

The force between a pair of charges is 900 newtons. The distance between the charges is 0.01 meters. If one of the charges is 2e

Maksim231197 [3]

Answer:

$\fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}$

Explanation:

Given:

Force between pair of charges= 900 newtons

The distance between the charges = 0.01 meters

Strength of Charge first q1 = 2e-10 Coulomb

To find:

Strength of Charge second q2 = ____ Coulomb?

Solution:

We know that,

Force between two charges separate by distance r is given by the equation,

$|F| = K_e \frac{q1 \cdot \: q2}{ {r}^{2} } \\ 900 =K_e \frac{(2e - 10)\cdot \: q2}{ {0.01}^{2} } \\ 900 \times {10}^{ - 4} = K_e {(2e - 10)\cdot \: q2} \\ q2 = \frac{9 \times {10}^{ - 2} }{(2e - 10) K_e} \\ \\ \fbox{We \: know \: that \: e = 2.71 } \\ substituting \: the \: value \: \\ q2 = \frac{9 \times {10}^{ - 2} }{(2 \times 2.71 - 10)K_e} \\ q2 = \frac{0.09}{ - 4.58 K_e} \\ q2 = \frac{-0.0196}{K_e}\: coulomb$

$\fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}$

Thanks for joining brainly community!

3 0

2 years ago

2. Light with a wavelength of 478 nm lies in the blue region of the visible spectrum. Calculate the frequency of this light.

Feliz [49]

Answer:

I GUESS 204 MPHN

Explanation:

4 0

3 years ago