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3 years ago

What happens at the condensation point?

Physics

2 answers:

pychu [463]3 years ago

8 0

Answer:

Dew point is the temperature at which condensation happens. ... When warm air hits the cold surface, it reaches its dew point and condenses. This leaves droplets of water on the glass or can. When a pocket of air becomes full of water vapor, clouds form.

Explanation:

The temperature at which a material changes from a gas to a liquid; the same as the boiling point. Condensation is the process by which water vapor (gas) in the atmosphere turns into water (liquid state). It is the opposite of evaporation. ... As the surrounding temperatures fall (cool), the water vapor turns into very tiny particles of water and ice crystals.

levacccp [35]3 years ago

4 0

Answer:

Explanation:

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kvasek [131]

Answer:

(a) $\theta=62.31^{\circ}$

(b) $\theta=117.68^{\circ}$

Explanation:

It is given that,

Force acting on the particle, F = 12 N

Displacement of the particle, $d=(2.00i -4.00j+3.00k)\ m$

Magnitude of displacement, $d=\sqrt{2^2+4^2+3^2}= 5.38\ m$

(a) If the change in the kinetic energy of the particle is +30 J. The work done by the particle is given by :

$W=Fd\ cos\theta$

$\theta$ is the angle between force and the displacement

According to work energy theorem, the charge in kinetic energy of the particle is equal to the work done.

So,

$cos\theta=\dfrac{W}{Fd}$

$cos\theta=\dfrac{+30\ J}{12\times 5.38}$

$\theta=62.31^{\circ}$

(b) If the change in the kinetic energy of the particle is (-30) J. The work done by the particle is given by :

$cos\theta=\dfrac{W}{Fd}$

$cos\theta=\dfrac{-30\ J}{12\times 5.38}$

$\theta=117.68^{\circ}$

Hence, this is the required solution.

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3 years ago

By what factor must the amplitude of a sound wave be decreased in order to decrease the intensity by a factor of 2?

alina1380 [7]

I believe that the answer to the question asked above is the following

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so if you decrease the intensity by a factor of 2 the sound wave will also decrease by a factor of 2.

Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.

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