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elena-14-01-66 [18.8K]
3 years ago
8

An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.50 m in t

he first 3.00μs3.00μs after it is released. (a) What are the magnitude and direction of the electric field? (b) Are we justified in ignoring the effects of gravity? Justify your answer quantitatively.
Physics
1 answer:
Softa [21]3 years ago
5 0

Answer:

Explanation:

A. Using

E= ma/q

E=m/q(2s/t²)

So

E= 9.1x10^-31/1.6*10^-19( 2*4.5/ 3*10-12)

E=5.7NC

The electric field has to be downward since the force is positive that is upward

B.

The electron acceleration is of the order of 10^11 times greater so for practical purposes we neglect the effect of gravity

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Answer:

The time needed is T  = 16.8 s

Explanation:

From the question we are told that

      The magnitude of the stimulated acceleration due gravity is  a  =  0.5 g

        The diameter of the spaceship is  d =  35m

       

Generally the force acting on the spaceship is  

       F  =  ma

Given that the spaceship is rotating it implies that the force experienced by the occupant is a centripetal force so

      F  = \frac{mv^2}{r}

Thus  

       ma  =  \frac{mv^2}{r}

=>    \frac{v^2}{r}  =  a

      Generally the speed of this spaceship is mathematically represented as

      v =  \frac{2 \pi}{T}

=>    v^2  =   [\frac{2\pi}{T}] ^2

=>     \frac{\frac{4\pi^2 r^2}{T^2} }{r}  = 0.5g

=>       \frac{4 \pi^2 r }{T^2} =  0.5 g

=>         T  = \sqrt{ \frac{4\pi^2 r}{0.5g}}

substituting values

          T  = \sqrt{ \frac{4* (3.142)^2 *(35)}{0.5 * 9.8}}

         T  = 16.8 s

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In a transformer, energy is carried from the primary coil to the secondary coil by magnetic field in the iron core.

To find the answer, we have to know more about the transformer.

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